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Reika [66]
3 years ago
7

Find the indicated limit, if it exists. (2 points) limit of f of x as x approaches 0 where f of x equals 10 x plus 2 when x is l

ess than 0 and the absolute value of the quantity 2 minus x when x is greater than or equal to 0
Mathematics
1 answer:
nadya68 [22]3 years ago
4 0

Answer:

Q1: as x approaches 0 from left lim(10x+2)= 2 and as x approaches 0 from right lim(2-x)=2. Therefor, lim as x approaches 0 of f(x)=2

Q2: only one option that makes sense.... as (x-6) can not equal 0, x can not equal 6. Therefore, -inf ; 6

Q3: lim(x+10) as x approaches 8 from left does not equal lim(10-x) as x approaches 8 from right. Hence, limit does not exist.

Q4: lim(-4-x) as x approaches -10 from left = f(-10) = lim(x+16) as x approaches -10 from right = 6. So, answer is lim of f(x) as x approaches -10 = 6

Q5: an example would be (x+1)/((x+1)(x-1)) where (x+1) is removable at x=-1 and (x-1) is non-removable and creates an asymptote at x=1

Step-by-step explanation:

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levacccp [35]

Answer:

m(n) = 24 (0.75)^n

Step-by-step explanation:

1) <u>The two points are</u>:

a) On the first swing she swings forward by 18 degrees: <em>(1, 18)</em>

b) On the second swing she only comes 13.5 degrees forward: <em>(2,13.5)</em>

2) <u>The general equation using the form given is</u>:

m(n)=A(B)^n

3) <u>Substitute the two points</u>:

18=A(B)\\ \\ 13.5=A(B)^2

4) <u>Divide the second equation by the first one</u>:

⇒ 13.5 / 18 = B

⇒ B = 0.75

5) <u>Substitue B = 0.75 into the first equation</u>:

18 = A (0.75) ⇒ A = 18 / 0.75 = 24

Hence, the equation is:

m(n) = 24 (0.75)^n

5 0
3 years ago
The equation of a parabola is 18(y−5)2=x+3 . What are the coordinates of the focus? (−3, 7) (−5, 5) (−1, 5) (−3, 3)
aleksandrvk [35]
18(y-5)^2=x+3

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tankabanditka [31]

Answer:

The answer is definitely C

Step-by-step explanation:

Following the system of inequalities will graph this solution best on the graph, it is the inequality represented in the graph.

ur wlcm :)

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Exact:

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