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3 years ago

(50 POINTS)!

Mathematics

1 answer:

Yuliya22 [10]3 years ago

4 0

Answer:

The answer to your question is below

Step-by-step explanation:

When a denominator has a positive exponent we change it into an expression with a negative exponent and vice-versa, when a numerator has a positive exponent, we change it into a denominator with a negative exponent.

a) $\frac{1}{p^{4}}$ = p⁻⁴

b) $\frac{1}{25}$ = 25⁻¹

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What is 500% in a fraction in simplest form.

Mashutka [201]

100 is in a full fraction, so we have 5 100's. The answer is 5.

5 0

3 years ago

Read 2 more answers

Please help ASAP!! 31 points and brainliest!

jolli1 [7]

A relation is a function if it has only One y-value for each x-value. Functions f(2/3)=2/9 for f(x)=2x²-4x+2 and f(1/4)==-21/4 for f(x)=4x²+2x-6

<h3>What is a function?</h3>

A relation is a function if it has only One y-value for each x-value.

The given function is

f(x)=2x²-4x+2

Put x=2/3

f(2/3)=2(2/3)²-4(2/3)+2

=2(4/9)-8/3+2

=8/9-8/3+2

=(8-24+18)/9

f(2/3)=2/9

Now f(x)=4x²+2x-6

Put x=1/4

f(1/4)=4(1/4)²+2(1/4)-6

=4/16+2/4-6

=1/4+1/2-6

= 1+2-24/4

f(1/4)==-21/4

Hence functions f(2/3)=2/9 for f(x)=2x²-4x+2 and f(1/4)==-21/4 for f(x)=4x²+2x-6

To learn more on Functions click:

brainly.com/question/21145944

#SPJ1

3 0

1 year ago

Suppose the time a child spends waiting at for the bus as a school bus stop is exponentially distributed with mean 7 minutes. De

Gala2k [10]

Answer:

The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

Step-by-step explanation:

Let the random variable <em>X</em> represent the time a child spends waiting at for the bus as a school bus stop.

The random variable <em>X</em> is exponentially distributed with mean 7 minutes.

Then the parameter of the distribution is, $\lambda=\frac{1}{\mu}=\frac{1}{7}$ .

The probability density function of <em>X</em> is:

$f_{X}(x)=\lambda\cdot e^{-\lambda x};\ x>0,\ \lambda>0$

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

$P(6\leq X\leq 9)=\int\limits^{9}_{6} {\lambda\cdot e^{-\lambda x}} \, dx$

$=\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148$

Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

6 0

3 years ago

Identify the domain and range of each relation. Use a mapping diagram to determine whether the relation a function.

Xelga [282]

Answer:

Domains- 6, 5, 1, 7

Ranges- -7, -8, 4, 5

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3 years ago

Add a bicycle shop all bicycles are on sale for $25 off the regular price if P represents the regular price in dollars of a bicy

Allushta [10]

Answer:

p-25

Step-by-step explanation:

5 0

3 years ago