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JulsSmile [24]
3 years ago
5

Giving the 2 sides of the triangle, find the range of all possible lengths for the third side.

Mathematics
1 answer:
Zinaida [17]3 years ago
4 0

Answer:

  1. 2 < x < 16
  2. 3 < x < 19
  3. 14 < x < 18
  4. 4 < x < 16
  5. 13 < x < 47
  6. 0 < x < 10
  7. 1 < x < 7

Step-by-step explanation:

The minimum third side is the difference of the given sides; the maximum third side is their sum.

If you like, you can have a spreadsheet calculate these for you. That seems like more work than just doing them in your head.

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Which point lies on a circle with a radius of 5 units and center at P(6, 1)?
Delvig [45]
Hello : 
all points <span>lies on a circle with a radius of 5 units and center at P(6, 1)are : 
M(x,y) :  (x-6)² + (y-1)² = 25</span>
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3 years ago
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Fed [463]
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Find the general indefinite integral. (Use C for the constant of integration. Remember to use absolute values where appropriate.
Maru [420]

Answer:

9\text{ln}|x|+2\sqrt{x}+x+C

Step-by-step explanation:

We have been an integral \int \frac{9+\sqrt{x}+x}{x}dx. We are asked to find the general solution for the given indefinite integral.

We can rewrite our given integral as:

\int \frac{9}{x}+\frac{\sqrt{x}}{x}+\frac{x}{x}dx

\int \frac{9}{x}+\frac{1}{\sqrt{x}}+1dx

Now, we will apply the sum rule of integrals as:

\int \frac{9}{x}dx+\int \frac{1}{\sqrt{x}}dx+\int 1dx

9\int \frac{1}{x}dx+\int x^{-\frac{1}{2}}dx+\int 1dx

Using common integral \int \frac{1}{x}dx=\text{ln}|x|, we will get:

9\text{ln}|x|+\int x^{-\frac{1}{2}}dx+\int 1dx

Now, we will use power rule of integrals as:

9\text{ln}|x|+\frac{x^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}+\int 1dx

9\text{ln}|x|+\frac{x^{\frac{1}{2}}}{\frac{1}{2}}+\int 1dx

9\text{ln}|x|+2x^{\frac{1}{2}}+\int 1dx

9\text{ln}|x|+2\sqrt{x}+\int 1dx

We know that integral of a constant is equal to constant times x, so integral of 1 would be x.

9\text{ln}|x|+2\sqrt{x}+x+C

Therefore, our required integral would be 9\text{ln}|x|+2\sqrt{x}+x+C.

4 0
3 years ago
Observe the equation below, can a value be found for x to make the equation true? Why or why not? 0=4x
Fiesta28 [93]
You have written 0 = 4x.

The value of x that makes it true is x = 0, given that 4 times 0 is 0.

Nevertheless, I think you wanted to write 0 = 4 ^x (this is 4 raised to the power 4).

In that case, there is not any valued of x that satisfies the equation. This is, the equation is always false.

That is because, there is not any value of x for which 4^x is zero. The range of this function is al the positive values of x, which exclude zero.
3 0
3 years ago
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stiv31 [10]

Answer:

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Step-by-step explanation:

We have 2 points so we can find the slope

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We can use the slope intercept form of the equation

y= mx+b  where m is the slope and b is the y intercept

y = 2x-3

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3 years ago
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