Giving the 2 sides of the triangle, find the range of all possible lengths for the third side.
1 answer:
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Answer:
Option D. All values of x make the equation true
Step-by-step explanation:
<u><em>The options of the question are</em></u>
a.The result is not correct because Step 2 has an error.
b.The solution is x=7.
c.No values of x make the equation true.
d.All values of x make the equation true
we have the equation
solve for x
Apply distributive property right side
Combine like terms
subtract 4x both sides
The equation has infinity solutions
.All values of x make the equation true
I'm not sure if this is the easiest way of doing this, but it surely work.
Let the base of the triangle be AB, and let CH be the height. Just for reference, we have
Moreover, let CH=y and BC=z
Now, AHC, CHB and ABC are all right triangles. If we write the pythagorean theorem for each of them, we have the following system
If we solve the first two equations for y squared, we have
And we can deduce
So that the third equation becomes
(we can't accept the negative root because negative lengths make no sense)