\left[x _{2}\right] = \left[ \frac{-1+i \,\sqrt{3}+2\,by+\left( -2\,i \right) \,\sqrt{3}\,by}{2^{\frac{2}{3}}\,\sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}+\frac{\frac{ - \sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}{24}+\left( \frac{-1}{24}\,i \right) \,\sqrt{3}\,\sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}{\sqrt[3]{2}}\right][x2]=⎣⎢⎢⎢⎢⎡2323√(432by+√(−6912+41472by+103680by2+55296by3))−1+i√3+2by+(−2i)√3by+3√224−3√(432by+√(−6912+41472by+103680by2+55296by3))+(24−1i)√33√(432by+√(−6912+41472by+103680by2+55296by3))⎦⎥⎥⎥⎥⎤
totally answer.
All 3 equations the Answer is v= 13/2
Divide 5 by 89 and you get a=17.8
Answer:4
Step-by-step explanation:
f(1)=6(1)+2
=8
g(f(1))=2(8)+4/5
=20/5
=4
Answer:
There are 48 numbers that satisfy the condition
Step-by-step explanation:
Find the relationship between 3 and 12
3 * 4 = 12
The maximum number of multiples of 12 within 200 is 18.
The maximum number of multiples within 200 is 66.
So the number of numbers within 200 that go exactly into 3 but not exactly into 12 is:
66-18 = 48
