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lions [1.4K]
2 years ago
14

Use quadratic formula to solve the equation: 12x^2-17x+6 =0

Mathematics
1 answer:
Flura [38]2 years ago
3 0
For ax<span>²+bx+c=0
x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}

so

12x</span><span>²-17x+6=0
a=12
b=-17
c=6

</span>
<span>x=\frac{-(-17)+/- \sqrt{(-17)^2-4(12)(6)} }{2(12)}
</span><span>x=\frac{17+/- \sqrt{289-288} }{24}
</span><span>x=\frac{17+/- \sqrt{1} }{24}
</span>x=\frac{17+/- 1}{32}
x=\frac{17+1}{32} or \frac{17-1}{32}
x=\frac{18}{32} or \frac{16}{32}
x=9/16 or 1/2
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A 2-column table with 5 rows titled Length Conversion. Column 1 is labeled Inches, x with entries 2, 4, 7, 10, 13. Column 2 is l
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a) en cuántas filas la suma es igual?

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Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Determine two pairs of polar coordinates for (3,-3) when 0
Xelga [282]

The two pairs of polar coordinates for the given point (3, -3) with 0° ≤ θ < 360° are (3√2, 135°) and (3√2, 315°).

<h3>What is a polar coordinate?</h3>

A polar coordinate is a two-dimensional coordinate system, wherein each point on a plane is typically determined by a distance (r) from the pole (origin) and an angle (θ) from a reference direction (polar axis).

Next, we would determine the distance (r) and angle (θ) as follows:

r = √(3² + (-3)²)

r = √(9 + 9)

r = 3√2.

θ = tan⁻¹(-3/3)

θ = tan⁻¹(-1)

θ = 3π and 7π/4 (second and fourth quadrants).

Converting to degrees, we have:

θ = 135° and 315°.

Read more on polar coordinates here: brainly.com/question/3875211

#SPJ1

Complete Question:

Determine two pairs of polar coordinates for the point (3, -3) with 0° ≤ θ < 360°

5 0
1 year ago
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