Question

Use quadratic formula to solve the equation: 12x^2-17x+6 =0

Answer 1

For ax²+bx+c=0
x=$\frac{-b+/- \sqrt{b^2-4ac} }{2a}$

so

12x²-17x+6=0
a=12
b=-17
c=6


x=$\frac{-(-17)+/- \sqrt{(-17)^2-4(12)(6)} }{2(12)}$
x=$\frac{17+/- \sqrt{289-288} }{24}$
x=$\frac{17+/- \sqrt{1} }{24}$
x=$\frac{17+/- 1}{32}$
x=$\frac{17+1}{32}$ or $\frac{17-1}{32}$
x=$\frac{18}{32}$ or $\frac{16}{32}$
x=9/16 or 1/2