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Identify the coefficient of the term.<br> - 7X/2

kompoz [17]

Answer:

The answer is -7.

Step-by-step explanation:

A coefficient is a number placed before and multiplying the variable in an algebraic expression e.g. (4 in 4x)

4 0

3 years ago

Hey answer this those who know?

Makovka662 [10]

Answer:

do like this i think answer is correct

8 0

3 years ago

Office occupancy in a city is an indication of the economic health of the region in which it is located. A random sample of offi

Pani-rosa [81]

Answer:

$(0.13-0.1) - 2.58 \sqrt{\frac{0.13(1-0.13)}{165} +\frac{0.10(1-0.10)}{140}}=-0.0664$

$(0.13-0.1) + 2.58 \sqrt{\frac{0.13(1-0.13)}{165} +\frac{0.10(1-0.10)}{140}}=0.124$

We are confident at 99% that the difference between the two proportions is between $-0.0664 \leq p_1 -p_2 \leq 0.124$ . And since the confidence interval cotains the value 0 we don't have enough evidence to conclude that we have significant differences between the to proportions in these two cities

Step-by-step explanation:

$p_1$ represent the real population proportion for 1

$\hat p_1 =\frac{22}{165}=0.13$ represent the estimated proportion for 1

$n_1=165$ is the sample size required for 1

$p_2$ represent the real population proportion for 2

$\hat p_2 =\frac{14}{140}=0.10$ represent the estimated proportion for 2

$n_2=140$ is the sample size required for 2

$z$ represent the critical value for the margin of error

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_1 -\hat p_2) \pm z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}$

For the 99% confidence interval the significance is $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , and the critical value using the normal standard distribution.

$z_{\alpha/2}=2.58$

Replacing we got:

$(0.13-0.1) - 2.58 \sqrt{\frac{0.13(1-0.13)}{165} +\frac{0.10(1-0.10)}{140}}=-0.0664$

$(0.13-0.1) + 2.58 \sqrt{\frac{0.13(1-0.13)}{165} +\frac{0.10(1-0.10)}{140}}=0.124$

We are confident at 99% that the difference between the two proportions is between $-0.0664 \leq p_1 -p_2 \leq 0.124$ . And since the confidence interval cotains the value 0 we don't have enough evidence to conclude that we have significant differences between the to proportions in these two cities

8 0

3 years ago

This one please help out

miskamm [114]

Sorry i don’t know the answer.

3 0

3 years ago

Read 2 more answers

How do I 'Factor the expression 12p+30.' ?

s2008m [1.1K]

Answer:

Grouping and then use the common factor. Therefor the answer is 6(2p+5)