. x + (x + 2)≤166
. 2x+2≤166
. x≤83 - 1
. x≤82
. x=81
. 81+(81+2)=164; 164<166
answer: 81 and 83
There is not an answer to an expression.
-3+p is an expression, unless there was an equal sign and a sum at the end, that is when we can solve for the variable x.
-3+p simply equals -3+p
Answer: $4
The cost of an 8x10 piece is $2, and 16x20 is just 2 times that amount, multiply the cost.
Step-by-step explanation:
problem 1.
1. 6y = 30
2. y = 5
3. 3x + 2(5) = 16
4. 3x+10=16
5. 3x=6
6. x=2
solution: (2,5)
problem 2.
1. x=7
2. 4(2)-2y=18
3. 28-2y=18
4. -2y= -10
5. y=5
solution (7,5)
problem 3
10x=10
x=1
7(1) +y =-2
y=-9
(1,9)
problem 4
0= -6
no solution
problem 5
0=0
Infinite many
Answers:
- Exponential and increasing
- Exponential and decreasing
- Linear and decreasing
- Linear and increasing
- Exponential and increasing
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Explanation:
Problems 1, 2, and 5 are exponential functions of the form
where b is the base of the exponent and 'a' is the starting term (when x=0).
If 0 < b < 1, then the exponential function decreases or decays. Perhaps a classic example would be to study how a certain element decays into something else. The exponential curve goes downhill when moving to the right.
If b > 1, then we have exponential growth or increase. Population models could be one example; though keep in mind that there is a carrying capacity at some point. The exponential curve goes uphill when moving to the right.
In problems 1 and 5, we have b = 2 and b = 1.1 respectively. We can see b > 1 leads to exponential growth. I recommend making either a graph or table of values to see what's going on.
Meanwhile, problem 2 has b = 0.8 to represent exponential decay of 20%. It loses 20% of its value each time x increases by 1.
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Problems 3 and 4 are linear functions of the form y = mx+b
m = slope
b = y intercept
This b value is not to be confused with the previously mentioned b value used with exponential functions. They're two different things. Unfortunately letters tend to get reused.
If m is positive, then the linear function is said to be increasing. The line goes uphill when moving to the right.
On the other hand if m is negative, then we go downhill while moving to the right. This line is decreasing.
Problem 3 has a negative slope, so it is decreasing. Problem 4 has a positive slope which is increasing.