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3 years ago

A) 3 in b) 4 in c) 5 in d) 6 in PLEASE HELP

Mathematics

1 answer:

Andrei [34K]3 years ago

8 0

Answer:

I would say A

Step-by-step explanation:

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HELP ME ASAP WITH MATH MONEY & WAGES

Dennis_Churaev [7]

Answer:

96,220

Step-by-step explanation:

187,400 x .3 (30%)= 56,220

56220+40000= *96,220

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3 years ago

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Archy [21]

Answer:

Step-by-step explanation:

78x9=702

702/6=117 minutes.

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3 years ago

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Uhhh please help me. I dont know why i dont understand this problem

Mariana [72]

The answer is A) because the parabola is less than 3 (open circle) and the line is greater than and equal to 3 (closed circle)

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3 years ago

If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w

MatroZZZ [7]

Let $x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11}$ be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

$\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.$

2. If the mean weight of the 7 other players is 202 lb, then

$\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.$

3. From the previous statements you have that

$x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.$

Add these two equalities and then divide by 11:

$x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.$

Answer: the mean weight of the 11-person team is $208\dfrac{10}{11}\ lb.$

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3 years ago

Match the decimal with its equivalent percent.

seraphim [82]

Answer:

42%

Step-by-step explanation:

decimal * 100 to get %

8 0

2 years ago