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irina1246 [14]
3 years ago
11

A person is asked to randomly pick two balls from a bag which has 15 red and 5 blue balls. The probability that the person picks

two balls of the same colour is
Mathematics
2 answers:
Murrr4er [49]3 years ago
7 0
You pick 2 balls and they can be of the same colour if either both of them are blue or both are red, i.e. the effective probability(P) = P(RR)(both are red) + P(BB)(both are blue)

1: Both the balls are blue
The number of ways of picking up a blue ball out of 20 balls are 5/20. Number of ways of picking up a second blue ball are 4/19.
Thus probability of picking up 2 blue balls P(BB) = 5/20 * 4/19 = 20/380

2: Both the balls are red
The number of ways of picking up a red ball out of 20 balls are 15/20.
Number of ways of picking up a second red ball are 14/19.
Thus the probability of picking up 2 black balls P(RR) = 15/20* 14/19 = 210/380

<span>Thus the effective probability P = 20/380+ 210/380 = 230/380= 23/38.</span>
DedPeter [7]3 years ago
5 0
<span>Total sample space = 20C2 = 190 The number of ways of selecting 2 balls of same color from a suit of 15 red balls 15C2 = 105 The number of ways of selecting 2 balls of same color from a suit of 5 blue balls 5C2 = 10 Thus the probability that the person picks 2 balls of same color = [105/190 + 10/190] = 115/190 = 23/38</span>
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prisoha [69]

Given:

In a right angle triangle ABC, \angle B=90^\circ,x=8.7\ m, and \theta = 45^\circ

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Solution:

In a right angle triangle,

\cos \theta =\dfrac{Adjacent}{Hypotenuse}

\cos \theta =\dfrac{BC}{AC}

\cos (45^\circ) =\dfrac{8.7}{AC}

\dfrac{1}{\sqrt{2}}=\dfrac{8.7}{AC}

On cross multiplication, we get

AC=8.7\times \sqrt{2}

AC=12.30365799

AC\approx 12.304

Therefore, the measure of AC is 12.304 m.

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Step-by-step explanation:

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