So try to isolate a by division and such
K=4a+9ab
we use reverse dstributive which is ab+ac=a(b+c) so
undistribute a
4a+9ab=a(4+9b)
k=a(4+9b)
divide both sides by (4+9b)
=a
a=
Answer:
This is proved by ASA congruent rule.
Step-by-step explanation:
Given KLMN is a parallelogram, and that the bisectors of ∠K and ∠L meet at A. we have to prove that A is equidistant from LM and KN i.e we have to prove that AP=AQ
we know that the diagonals of parallelogram bisect each other therefore the the bisectors of ∠K and ∠L must be the diagonals.
In ΔAPN and ΔAQL
∠PNA=∠ALQ (∵alternate angles)
AN=AL (∵diagonals of parallelogram bisect each other)
∠PAN=∠LAQ (∵vertically opposite angles)
∴ By ASA rule ΔAPN ≅ ΔAQL
Hence, by CPCT i.e Corresponding parts of congruent triangles PA=AQ
Hence, A is equidistant from LM and KN.
Answer:
Ainsworth (1970) identified three main attachment styles, secure (type B), insecure avoidant (type A) and insecure ambivalent/resistant (type C).
Step-by-step explanation:
For example, Schaffer and Emerson suggested that attachments develop in four stages: asocial stage or pre-attachment (first few weeks), indiscriminate attachment (approximately 6 weeks to 7 months), specific attachment or discriminate attachment (approximately 7-9 months) and multiple attachment (approximately 10
Let X = smallest angle
largest 3x
middle=2x. add the 3 angles of any triangle and you get ,180
x+2x+3x=180
6x=180
x= 30
smallest =30
middle=60
largest=90
Answer:
9/4
Step-by-step explanation:
1. 
2. 
3. 
Therefore, the slope is 9/4.
