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Nitella [24]
3 years ago
12

0.43 times 2 whats is the awnser

Mathematics
1 answer:
il63 [147K]3 years ago
5 0

Answer: 0.86

Step-by-step explanation:

You might be interested in
Factor this expression. x2 + 9x + 16
Alexxandr [17]

Answer:

Read below.

Step-by-step explanation:

Hey there, grab your solution:

x²+9x+16=0

Sqrt(D)=sqrt(17)

So x is:

(-9+sqrt(17))/2

And (-9-sqrt(17))/2

3 0
3 years ago
PLEASE HELP!
Cloud [144]
The short answer is trial and error.  The side lengths "3" and "4" can both be substituted for a² and b² but not c² because their value squared is not high enough since 5² is 25. "c²" as to match the longest side because the smaller numbers will cause the equation to not be true. See Below. 

a² + b² = c²
3² + 4² = 5²
9 + 16 =  25
25 = 25
______________________________

a² + b² = c²
4² + 3² = 5²
16 + 9 = 25
25 = 25
______________________________

a² + b² = c²
5² + 4² = 3²
25 + 16 = 9
41 ≠ 9

______________________________

a² + b² = c²
3² + 5² = 4²
9 + 25 = 16
34 ≠ 16

Hope this helped!
7 0
3 years ago
Starting from rest the motor boat travels around the circular path (radius of curvature= 40 m),at a speed (v= 0.8 t m/s),where (
dsp73

Answer:

The magnitude of the boat's velocity is 5.66 m/s

Step-by-step explanation:

Given;

Radius of curvature of the circular path, r = 40 m

speed of the boat, v = 0.8 t m/s

The magnitude of the boat's velocity when it has traveled 20 m is ?

a = dv / dt,

v = 0.8 t (differentiate with respect to t)

dv / dt = 0.8 = a

thus, a = 0.8 m/s²

If the boat starts from rest, initial velocity, u = 0

Apply kinematic equation, to solve for the boat velocity at 20 m

v² = u² + 2as

v² = 0 + 2 x 0.8 x 20

v² = 0 + 32

v² = 32

v = √32

v = 5.66 m/s

Therefore, the magnitude of the boat's velocity when it has traveled 20 m is 5.66 m/s

7 0
3 years ago
The time to complete a standardized exam is approximately normal with a mean of 70 minutes and a standard deviation of 10 minus.
AnnyKZ [126]

Answer:

Step-by-step explanation:

Given that the  time to complete a standardized exam is approximately normal with a mean of 70 minutes and a standard deviation of 10 minutes.

P(completing exam before 1 hour)

= P(less than an hour) = P(X<60)

=P(Z<\frac{60-70}{10} =-1)

=0.5-0.34=0.16

i.e. 16% of students completed the standardized exam.

7 0
3 years ago
Given m||n, find the value of x
Soloha48 [4]

Answer:

(i)Here ∠HGB=∠AGE(vertically opposite angles)

∠HGB=110

∘

Now, for parallel lines l and m, with transversal t.

∠HGB+∠GHD=180

∘

(Angles on the same side of the transversal are supplementary)

110

∘

+∠GHD=180

∘

∠GHD=180

∘

−110

∘

=70

∘

(ii)For parallel lines l and m with transversal a

∠AIE=∠CJI (corresponding angles)

⇒x=100

∘

4 0
3 years ago
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