All categories

3 years ago

The table below shows the account balances for four different customer accounts at the City

Mathematics

2 answers:

Ainat [17]3 years ago

6 0

Answer:

the answer is $-24

Step-by-step explanation:

i just took the test

PolarNik [594]3 years ago

4 0

Answer: 25 because it’s in between both numbers

You might be interested in

The locus of points in a plane 1 unit from the point (0,0)

xeze [42]

Answer:

x² + y² = 1

Step-by-step explanation:

A circle is the locus of a point such that its distance from a fixed point (known as the origin) is always constant. The general equation of a circle is given as:

$(x-h)^2+(y-k)^2=r^2$

Where (h, k) is the center of the circle and r is the radius of the circle.

Given that the plane is 1 unit from the point (0,0). Therefore the radius of the circle is 1 unit and the center of the circle is (0, 0). Therefore the equation of the circle is:

$(x-0)^2+(y-0)^2=1^2\\\\x^2+y^2=1$

3 0

3 years ago

A right triangle has one side that measures 4in. The angle opposite that side measures 80 degrees. What is the length of the hyp

Crazy boy [7]

Hello from MrBillDoesMath!

Answer:

4/sin(80)

which is approximately 4.06

Discussion:

From the triangle, not drawn too accurately (see attachment)

sin(80) = side opposite /hypotenuse =>

sin (80) = 4/c => multiply both sides by "c"

c sin(80) = 4/c * c =>

c sin(80) = 4 => divide both sides by sin(80)

c = 4/sin(80)

and 4/sin(80) is approximately 4.06

Thank you,

MrB

6 0

3 years ago

Suppose that A and B are nonsingular matrices. Then AB is also nonsingular. Furthermore, a theorem from linear algebra then stat

kherson [118]

Answer:

A) Verified

B) Proved

Step-by-step explanation:

a) Let's verify it for 2 x 2 matrix,

$A=\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]$ and $B=\left[\begin{array}{ccc}e&f\\g&h\end{array}\right]$

$AB=\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]\left[\begin{array}{ccc}e&f\\g&h\end{array}\right]=\left[\begin{array}{ccc}a.e+b.g&a.f+b.h\\c.e+d.g&c.f+d.h\end{array}\right]$

$(AB)^{-1}=\frac{1}{(a.e+b.g)(c.f+d.h)-(a.f+b.h)(c.e+d.g)}\left[\begin{array}{ccc}c.f+d.h&-(a.f+b.h)\\-(c.e+d.g)&a.e+b.g\end{array}\right]$

$A^{-1}=\frac{1}{a.d-b.c} \left[\begin{array}{ccc}d&-b\\-c&a\end{array}\right]$

$B^{-1}=\frac{1}{e.h-f.g} \left[\begin{array}{ccc}h&-f\\-g&e\end{array}\right]$

$B^{-1}A^{-1}=\frac{1}{(a.e+b.g)(c.f+d.h)-(a.f+b.h)(c.e+d.g)}\left[\begin{array}{ccc}c.f+d.h&-(a.f+b.h)\\-(c.e+d.g)&a.e+b.g\end{array}\right]$

So it is proved that the results are same.

b) Now, let's prove it for any n x n matrix.

$(AB)(AB)^{-1}=I\\\\A^{-1}(AB)(AB)^{-1}=A^{-1}I\\\\IB(AB)^{=1}=A^{-1}I\\\\B(AB)^{=1}=A^{-1}\\\\B^{-1}B(AB)^{=1}=B^{-1}A^{-1}\\\\I(AB)^{=1}=B^{-1}A^{-1}\\\\(AB)^{=1}=B^{-1}A^{-1}$

8 0

3 years ago

Radius of 8 find the area?

sergejj [24]

C= πr²
C= 3.14×8²
C=3.14×64
C=200.96

5 0

3 years ago

Anna inherits $70000 and decides to invest part of it in an education account for her daughter and the rest in a 5 year CD. If t

TEA [102]

E = amount she put for Education

CD = amount she put for a Certificate of Deposit.

so, whatever those amounts are, we know that all she got is 70,000 bucks total, so E + CD = 70000.

how much is three times the CD? well, 3*CD or 3CD.

how much is 10,000 more than that? well 3CD + 10000.

since we know that the amount on Education was 10000 more than three times the CD, then E = 3CD + 10000.

$\bf \begin{cases}
E+CD=70000\implies \boxed{CD}=70000-E\\
E=3CD+10000\\
------------------\\
E=3\left( \boxed{70000-E}\right)+10000
\end{cases}
\\\\\\
E=210000-3E+10000\implies 4E=200000\implies E=\cfrac{200000}{4}
\\\\\\
E=50000$

how much was it invested in the CD? well, CD = 70000 - E.

5 0

3 years ago

Read 2 more answers