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3 years ago

A bag contains eight black cards numbered 1 through 8 and six red cards numbered 1 through 6. You choose a card at random.

Mathematics

1 answer:

Tems11 [23]3 years ago

5 0

Answer:

What is the question to this? I can help to find the answer probably but i dont know what i'm looking for. is it probability?

Step-by-step explanation:

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Mr. De Vries a hoard of 62 nickels and dimes whose value was $ 4.90. Find the number of nicked and dimes. Then if the nickels we

avanturin [10]

D gooidddd llluuuccckkk

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3 years ago

GIVING OUT BRAINLIST ASAP

vlada-n [284]

Answer: John wil spend $25.49 total.

Step-by-step explanation:

First add up the costs of each item, so $6 + $10 +$7.50. That total is $23.50. Next, add the tax (8.5%) to that total, which brings us to $23.49

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3 years ago

What number is lower -162 or 159

vovikov84 [41]

Answer:

-162

Step-by-step explanation:

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3 years ago

Read 2 more answers

Alex wants to buy cupcakes for his work office but also does not want to spend over $25 because he doesn't like his co workers *

natka813 [3]

Answer:

16 cupcakes

Step-by-step explanation:

Amount Alex wants to spend = $25

Cost of each cupcake = $1.50

what is the max number of

cupcakes that Alex can buy without going over his $25 limit?

Let

x = maximum number of cupcakes Alex can buy

Amount Alex wants to spend = Cost of each cupcake * maximum number of cupcakes Alex can buy

25 = 1.50x

x = 25 / 1.50

x = 16.67

The maximum number of cupcakes that Alex can buy without going over his $25 limit is 16 cupcakes as a whole

7 0

3 years ago

A padlock for your gym locker uses a three number sequence to open the lock. if the numbers go from 1 to 28, how many different

aalyn [17]

Answer:

19,656

Step-by-step explanation:

Numbers used in locker = 3

Total numbers available = 28

Repetition is not allowed, so one number can be used only once. The order of number matters in the locker e.g. 123 password is not the same as 231. Since, the order of numbers matter, this is a problem of permutations. We need to find the number of different sequences formed with 28 numbers taken 3 at a time. This can be represented as 28P3

The formula for permutations is:

$^{n}P_{r}=\frac{n!}{(n-r)!}$

For the given case, we will have:

$^{28}P_{3}=\frac{28!}{(28-3)!}\\\\ = \frac{28!}{25!}\\\\ = 19656$

This means, 19,656 different 3 numbered sequences are possible for the locker.

8 0

3 years ago