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Tamiku [17]
3 years ago
13

A padlock for your gym locker uses a three number sequence to open the lock. if the numbers go from 1 to 28, how many different

sequences are on the dial without repeating a number?
Mathematics
1 answer:
aalyn [17]3 years ago
8 0

Answer:

19,656

Step-by-step explanation:

Numbers used in locker = 3

Total numbers available = 28

Repetition is not allowed, so one number can be used only once. The order of number matters in the locker e.g. 123 password is not the same as 231. Since, the order of numbers matter, this is a problem of permutations. We need to find the number of different sequences formed with 28 numbers taken 3 at a time. This can be represented as 28P3

The formula for permutations is:

^{n}P_{r}=\frac{n!}{(n-r)!}

For the given case, we will have:

^{28}P_{3}=\frac{28!}{(28-3)!}\\\\ = \frac{28!}{25!}\\\\ = 19656

This means, 19,656 different 3 numbered sequences are possible for the locker.

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Aaron is making a jewelry box of wood in the shape of a rectangular prism the jewelry box will have the dimensions shown in the
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Answer:

b. $342

Step-by-step explanation:

Base = Length * width

Base Area = 12 * 5

B = 180 square inches.

Perimeter of the prism will be :

P = 2 (length) + 2 (15)

P = 2 * 12 + 30

P = 54 inches

Height of the jewelry container will be :

X = Ph + 2B

X = 54 * 6 + 2 * 180

X = 684 square inches.

Total cost for paint of jewelry box is :

X * cost per inch

Total cost = 682 * $0.50

Total Cost = $342.

8 0
2 years ago
The flagpole is 20 ft high and casts an 8 foot shadow, the oak tree casts a 12 foot shadow. How tall is the oak tree
Fudgin [204]
Answer: 4.8 ft

To answer this question you need to know how much shadow: actual height ratio. Flagpole is having 8 ft shadow with 20 ft actual height. The ratio should be= 8 ft: 20 ft= 0.4

Then multiply the ratio with the oak tree shadow. The equation would be:
0.4 x 12 ft= 4.8 ft  
7 0
3 years ago
I need help with math please
ASHA 777 [7]

Answer:

greater than cb and less than ab ig

7 0
3 years ago
Among 500 freshmen pursuing a business degree at a university, 315 are enrolled in an economics course, 213 are enrolled in a ma
scoundrel [369]

Answer:

Step-by-step explanation:

Given that among 500 freshmen pursuing a business degree at a university, 315 are enrolled in an economics course, 213 are enrolled in a mathematics course, and 123 are enrolled in both an economics and a mathematics course.

From the above we find that

a) either economics of Math course is

315+213-123 =405

Out of 500 students 405 have taken either Math or Economics

Hence

c) student who have taken neither = 500-405 =95

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= 405-123 = 282

3 0
3 years ago
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Gwar [14]

Answer:

A

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supplementary angles add up to 180

angle cgr and kga are vertical angles so they are equal

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6 0
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