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2 years ago

Suppose P(C/D)=0.34, P(D)=0.11 , and P(D/C)=0.09. What is P(C) rounded to two decimal places?

Mathematics

2 answers:

Alex Ar [27]2 years ago

8 0

Answer:

0.42 ( APEX)

Step-by-step explanation:

From The Information Given

P(C | D) = P(C∩D)/P(D)

P(D | C) = P(C∩D)/P(C)

Therefore

P(C∩D) = P( C | D) × P(D)=P(D | C) × P(C)

P(C∩D) = 0.34×0.11

=<u>0.0374</u>

P(C)=P(C∩D)/P(D | C)

=0.0374/0.09

=0.415

Simplify

0.42

Therefore Your Answer Is : 0.42

Olegator [25]2 years ago

3 0

So C/D=.34 And D=.11, now just plug D into the first equation.

C/.11=.34 Divide by .11

C=3.09090909

Now this rounded two decimal places is 3.09!

Hope this helps

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If an event has a 55% chance of happening in one trial, how do I determine the chances of it happening more than once in 4 trial

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<h3>How to determine the number</h3>

From the information given, we have can deduce that;

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We are to find the probability of it happening more than once in 4 different trials

If the probability of it happening in one trial is 555 which equals 0. 55

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Learn more about probability here:

brainly.com/question/24756209

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