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Akimi4 [234]
3 years ago
11

Divide: 8xy^2 - 14y^2/2y Answers: 4xy^2-7y^2 4x-7 4xy-7y 4y-7x

Mathematics
1 answer:
Kruka [31]3 years ago
4 0
Answer would be 4xy-7y.

I have also given you the steps and working for this question. :)

You might be interested in
PLEASE HELP
Oksana_A [137]

Answer:

A racer has just completed his first lap at a speed of 198m/s. Now his speed decrease or he decelerateted at 195m/s after 2s of his completion of first lap, as soon as he saw a curve path(line segment R). He then moved at a constant speed of 195m/s for the next 2s(line segment s). Then the race track after 4s of the completion of first lap was straight, so the racer accelerated to 200m/s within 2s( line segment T) and traveled at a constant speed for the next 6s( line segment U). After 12s from the first lap completion, he immediately saw a curve track, so he decelerateted to the speed of 194m/s within 3s( line segment V).

Hope it helped.

please mark brainliest

4 0
2 years ago
Solve the equation using square roots. x2 + 10 = 9
Oksana_A [137]
x^2 + 10 = 9

Subtract 10 from both sides.

x^2 = -1

Since the square of a number, x, equals a negative number, -1, the answer cannot be a real number because the square of a real number is always non-negative. Therefore, there is no real number solution to this equation.

Answer: <span>B. no real number solutions</span>
5 0
3 years ago
A population has a standard deviation of 5.5. What is the standard error of the sampling distribution if the sample size is 81?
VladimirAG [237]

Answer:

\sigma = 5.5

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution \bar X and for this case we know that the distribution is given by:

\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})

And the standard error would be:

\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}

And replacing we got:

\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611

Step-by-step explanation:

For this case we know the population deviation given by:

\sigma = 5.5

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution \bar X and for this case we know that the distribution is given by:

\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})

And the standard error would be:

\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}

And replacing we got:

\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611

4 0
3 years ago
Last month, Ebony had 72 dollars in a checking account. The current balance is 126 dollars. What is the percent change in the ac
TEA [102]

Answer:

43%

Step-by-step explanation:

Last month, 72.

This month, 126.

Last month, ebony had 72/126 in her account to what she has this month. 72/126 as a percentage.

Ratio:

72:126

X100

7,200:12,600

÷126

57.142:100

Ebony had approximately 57% of her cash in her account last month, compared to this month.

5 0
3 years ago
How would I solve this
Feliz [49]
What are you solving for???
3 0
3 years ago
Read 2 more answers
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