<span>h= (-16t^2 + 28t + 7) </span>
find the derivative to get time<span>
<span>
h' = (-32t + 28)
When the ball reaches its maximum height, its
vertical velocity (h’) will be 0 </span></span>
<span>
<span>
0 = -32t + 28 </span></span>
-32t=-28
<span><span>-28/-32 = </span>0.875
seconds </span><span>
<span>
The ball reaches its maximum height in 0.875
seconds after being thrown; plug and chug and:
h= (-16(0.875)^2 + 28(0.875) + 7) = 19.25 feet</span></span>
Max height = 19.25 feet, time = 0.88 seconds
x = 8
Since x = 8, you can plug in/substitute 8 for "x" in the equation:
2.82842
2.83 You answer is the 4th option
x = 9
Plug in 9 for "x" in the equation
4 Your answer is the 1st option
It would be a Wednesday.
Hope this is helpful!
Answer: 1,953,125
This is one single value and it is just a bit under 2 million.
Or more accurately, it's a bit over 1.9 million.
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Explanation:
- a = 5 = first term
- r = -5 = common ratio
Note that dividing any term by its previous term gets us the common ratio
- r = term2/term1 = -25/5 = -5
- r = term3/term2 = 125/(-5) = -5
The r value must stay the same the entire time, or else the sequence isn't geometric.
The nth term of any geometric sequence is a*(r)^(n-1). With the 'a' and 'r' values we found, we update that to 5(-5)^(n-1)
-----------------
To verify that is the correct nth term expression, plug in various values of n to compare it with the given sequence.
If we tried n = 2 for instance, then we find the 2nd term is
5(-5)^(n-1) = 5(-5)^(2-1) = -25
which matches what your teacher gave you. I'll let you verify the other terms.
-----------------
The last thing we need to do is plug in n = 9 and simplify
5(-5)^(n-1)
5(-5)^(9-1)
5(-5)^8
5(390625)
1,953,125 this is one single value (rather than 3 separate values)
Answer:
(b) 5.5 × 10^-6
Step-by-step explanation:
hope if helps
