All categories

2 years ago

To improve readability,______ use text on a dark green background.

2 answers:

7 0

To improve readability, use white text on a dark green background but <span>the darker text on a lighter background was rated more readable than lighter text on dark backgrounds according to survey in every color combination. Example, red text on white background is more readable than white text on red background.</span>

Lilit [14]2 years ago

3 0

Answer:

white

Explanation:

You might be interested in

eocs can be fixed locations, temporary facilities, or virtual structures with staff participating remotely.

levacccp [35]

EOCS can be fixed locations, temporary facilities, or virtual structures with staff participating remotely is a true statement.

<h3>What is the Emergency Operations Centers (EOC)?</h3>

Emergency Operations Centers is known to be part of the four NIMS Command and Coordination structures as the EOCs are known to be used in an off site locations where staff are gotten from a lot of agencies that come together to address some imminent kind of threats and hazards.

Therefore saying that EOCS can be fixed locations, temporary facilities, or virtual structures with staff participating remotely is a true statement.

Learn more about EOCS from

brainly.com/question/10794095

#SPJ1

5 0

1 year ago

The measure of the maximum amount of data that can travel through a computer’s communications path in a given amount of time is

STatiana [176]

Answer:

Bandwidth

Explanation:

Bandwidth is the rate of transfer of data in the given time. Its unit is Bit/sec.

It is used to measure the transfer rate of bit in a network.

4 0

3 years ago

A=4x^2.(x-2y)-20x.(2y-x)

Luda [366]

Answer:

please give point

6 0

2 years ago

Computer A has an overall CPI of 1.3 and can be run at a clock rate of 600 MHz. Computer B has a CPI of 2.5 and can be run at a

kirill115 [55]

Answer:

Check the explanation

Explanation:

CPI means Clock cycle per Instruction

given Clock rate 600 MHz then clock time is Cー 1.67nSec clockrate 600M

Execution time is given by following Formula.

Execution Time(CPU time) = CPI*Instruction Count * clock time = $\frac{CPI*Instruction Count}{ClockRate}$

for system A CPU time is 1.3 * 100, 000 600 106

= 216.67 micro sec.

for system B CPU time is $=\frac{2.5*100,000}{750*10^6}$

= 333.33 micro sec

c) Since the system B is slower than system A, So the system A executes the given program in less time

Hence take CPU execution time of system B as CPU time of System A.

therefore

216.67 micro = = $\frac{2.5*Instruction}{750*10^6}$

Instructions = 216.67*750/2.5

= 65001

hence 65001 instruction are needed for executing program By system B. to complete the program as fast as system A

3 0

3 years ago

What would the range(3, 9) function generate?

gregori [183]

Answer:

A, 3,6,9

is the answer

Explanation:

bc it count by

3 0

2 years ago