/ Looks up author of selected books
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Answer:
Explanation:
This code was written in Java. It creates the Cars class with the requested variables and methods. It also creates the TestCars class which asks the user for the necessary inputs and then creates three Cars objects and passes the input values to the constructors. Finally, it uses the show() method on each object to call the information. A test has been created and the output can be seen in the attached image below.
import java.util.Scanner;
class TestCars{
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.print("Enter Car Make: ");
String make1 = in.next();
System.out.print("Enter Car Model: ");
String model1 = in.next();
System.out.print("Enter Car Year: ");
int year1 = in.nextInt();
System.out.print("Enter Car Make: ");
String make2 = in.next();
System.out.print("Enter Car Model: ");
String model2 = in.next();
System.out.print("Enter Car Year: ");
int year2 = in.nextInt();
System.out.print("Enter Car Make: ");
String make3 = in.next();
System.out.print("Enter Car Model: ");
String model3 = in.next();
System.out.print("Enter Car Year: ");
int year3 = in.nextInt();
Cars car1 = new Cars(make1, model1, year1);
Cars car2 = new Cars(make2, model2, year2);
Cars car3 = new Cars(make3, model3, year3);
car1.show();
car2.show();
car3.show();
}
}
class Cars {
String makes, models;
int years;
public Cars(String makes, String models, int years) {
this.makes = makes;
this.models = models;
this.years = years;
}
public void show() {
System.out.println("Car's make: " + this.makes);
System.out.println("Car's model: " + this.models);
System.out.println("Car's year: " + this.years);
}
}
Answer:
Check the explanation
Explanation:
CPI means Clock cycle per Instruction
given Clock rate 600 MHz then clock time is Cー 1.67nSec clockrate 600M
Execution time is given by following Formula.
Execution Time(CPU time) = CPI*Instruction Count * clock time =
a)
for system A CPU time is 1.3 * 100, 000 600 106
= 216.67 micro sec.
b)
for system B CPU time is
= 333.33 micro sec
c) Since the system B is slower than system A, So the system A executes the given program in less time
Hence take CPU execution time of system B as CPU time of System A.
therefore
216.67 micro = =
Instructions = 216.67*750/2.5
= 65001
hence 65001 instruction are needed for executing program By system B. to complete the program as fast as system A