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4vir4ik [10]
3 years ago
5

Assume you have a byte-addressable machine that uses 32-bit word (integers are 32-bit) and you are storing the following informa

tion: the string Inventory followed by a value (569)10 followed by another string Price followed by a value (49.75)10. Also, assume that floating point numbers are stored as single-precision IEEE 754 with 127 excess. a) Show (as hex numbers with word boundary) how this is stored on a big-endian machine. b) Show (as hex numbers with word boundary) how this is stored on a little-endian machine.
Computers and Technology
1 answer:
Tresset [83]3 years ago
7 0

Answer:

Internet protocol, IP address are 32- bit binary numbers.

Explanation: Each 32- bit is represented in 4- 8 bits segments

a) 10,11,13,14,  0,0,10,13,  0,11,12,13,  11,12,13,14,  0,0,0,11,  0,0,13,14,  10,12,13,14, O,10,13,14

b)

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A shop will give discount of 10% if the cost of purchased quantity is more than 1000. Ask user for quantity suppose, one unit wi
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Answer:

The program in C++ is as follows:

#include <iostream>

using namespace std;

int main(){

   int qty;

   float discount = 0;

   cout<<"Quantity: ";

   cin>>qty;

   int cost = qty * 100;

i f (cost > 1000) {        discount=cost * 0.10;        }

   cout<<"Cost: "<<cost - discount;

   return 0;

}

Explanation:

This declares the quantity as integer

   int qty;

This declares and initializes discount to 0

   float discount = 0;

This prompts the user for quantity

   cout<<"Quantity: ";

This gets input for quantity

   cin>>qty;

This calculates the cost

   int cost = qty * 100;

If cost is above 1000, a discount of 10% is calculated

i f (cost > 1000) {        discount=cost * 0.10;        }

This prints the cost

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7 0
3 years ago
The data below represents the yearly earnings (in $1000s of dollars) that high school and college (BS) graduates earn at a small
Taya2010 [7]

Answer:

library(moments)

library(readxl)

Exam1Q1 <- read_excel("Exam1Q1.xlsx")

View(Exam1Q1)

## Warning in system2("/usr/bin/otool", c("-L", shQuote(DSO)), stdout = TRUE):

## running command ''/usr/bin/otool' -L '/Library/Frameworks/R.framework/

## Resources/modules/R_de.so'' had status 1

plot(density(Exam1Q1$Highschool))

gostino.test(Exam1Q1$Highschool)

##  

##  D'Agostino skewness test

##  

## data:  Exam1Q1$Highschool

## skew = -0.24041, z = -0.69269, p-value = 0.4885

## alternative hypothesis: data have a skewness

agostino.test(Exam1Q1$BS)

##  

##  D'Agostino skewness test

##  

## data:  Exam1Q1$BS

## skew = 0.53467, z = 1.49330, p-value = 0.1354

## alternative hypothesis: data have a skewness

anscombe.test(Exam1Q1$Highschool)

##  

##  Anscombe-Glynn kurtosis test

##  

## data:  Exam1Q1$Highschool

## kurt = 2.56950, z = -0.29677, p-value = 0.7666

## alternative hypothesis: kurtosis is not equal to 3

anscombe.test(Exam1Q1$BS)

##  

##  Anscombe-Glynn kurtosis test

##  

## data:  Exam1Q1$BS

## kurt = 3.6449, z = 1.2599, p-value = 0.2077

## alternative hypothesis: kurtosis is not equal to 3

t.test(Exam1Q1$Highschool,Exam1Q1$BS, var.equal = T)

##  

##  Two Sample t-test

##  

## data:  Exam1Q1$Highschool and Exam1Q1$BS

## t = 0.16929, df = 76, p-value = 0.866

## alternative hypothesis: true difference in means is not equal to 0

## 95 percent confidence interval:

##  -1.131669  1.341926

## sample estimates:

## mean of x mean of y  

##  39.51282  39.40769

Explanation:

Summary:

The data set include two dependent variables which states High School annual earnings and BS annual earnings in the same small firm. Firstly, I used density plot function to view the distribution of two sets of variables. Secondly, I tested the skewness and kurtosis.Skewness of High School is -0.24041 which is left tail. Skewness of BS is 0.53476 which is right tail.Kurtosis of High School is 2.5695 which lower than 3 is platykurtic. Kurtosis of BS is 3.6449 which larger than 3 is leptokurtic. Thirdly, the sample population is 39 for each and has unknow standard deviation, so that I’m going to use t-test to perform the comparing analysis. The result shows p-value which equal to 0.866 is larger than significant value(alpha = 0.05). To the concludsion, there is no difference between yearly earnings of High School and of BS at a small firm.

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Dynamic random access memory
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