Assume you have a byte-addressable machine that uses 32-bit word (integers are 32-bit) and you are storing the following informa
tion: the string Inventory followed by a value (569)10 followed by another string Price followed by a value (49.75)10. Also, assume that floating point numbers are stored as single-precision IEEE 754 with 127 excess. a) Show (as hex numbers with word boundary) how this is stored on a big-endian machine. b) Show (as hex numbers with word boundary) how this is stored on a little-endian machine.
The formula and value to this question is "=A1+A3+A4+A5 with value 100"
Explanation:
The explanation of the given question as follows:
In question, it is defined that four cells that are "A1, A2, A3, and A4" contains value that are "10, 20, 30, and 40".
To add these values we use addition formula that is "=A1+A2+A3+A4". it will give value 100.
If the user inserts a new row that is "A2" and assigns a value in the cell that is "50" so, we use the above formula that adds values with these values we also use the value "100".
Some component of the hardware are central processing unit (CPU), monitor, mouse, keyboard, computer data storage, graphics card, sound card, speakers and motherboard.
I’m sure theirs more but here’s so. Hope this helps!
