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4vir4ik [10]
3 years ago
5

Assume you have a byte-addressable machine that uses 32-bit word (integers are 32-bit) and you are storing the following informa

tion: the string Inventory followed by a value (569)10 followed by another string Price followed by a value (49.75)10. Also, assume that floating point numbers are stored as single-precision IEEE 754 with 127 excess. a) Show (as hex numbers with word boundary) how this is stored on a big-endian machine. b) Show (as hex numbers with word boundary) how this is stored on a little-endian machine.
Computers and Technology
1 answer:
Tresset [83]3 years ago
7 0

Answer:

Internet protocol, IP address are 32- bit binary numbers.

Explanation: Each 32- bit is represented in 4- 8 bits segments

a) 10,11,13,14,  0,0,10,13,  0,11,12,13,  11,12,13,14,  0,0,0,11,  0,0,13,14,  10,12,13,14, O,10,13,14

b)

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Think back over the information presented in the lesson about how you can skillfully use the Internet when doing research. Selec
madreJ [45]

Avoid wikipedia, anyone can put answers down on there and make it seem correct but it is not. Do not trust any website research the websites or look at ratings if possible. Use the answers that google provides itself if possible. And research trusted websites.

If this helped please mark me as brainlest.

\left[\begin{array}{ccc}Thanks,\\JustSomeIdiot\end{array}\right]

7 0
3 years ago
What is the largest possible value that the variable x can have after the code segment executes? 17 17 A 14 14 B 11 11 C 4
Bogdan [553]

Answer:

i dont know sorry man no problem listed

Explanation:

6 0
2 years ago
Match the steps with the actions that are involved when an internal host with IP address 192.168.10.10 attempts to send a packet
Anna35 [415]

Answer:

Following are the steps with actions that are involved in required to perform a packet transfer.

Explanation:

  • Step 1: The host sends a connection request to server which is at IP address 209.165.200.254
  • Step 2: R1 check the configuration of NAT to inquire weather the packet should be translated or not.
  • Step 3: If there is no entry found for translation of given IP address, It is assumed that the IP address 192.168.10.10  will be translated already.
  • Step 4: R1 selects a global address  from the dynamic address pool that is available to it.
  • Step 5: R1 replaces the given IP address 192.168.10.10  with the translated inside global address.

i hope it will help you!

5 0
3 years ago
In this lab, you will build a system for package delivery services that provides different shipping options with specific price.
Alex73 [517]

Answer:

See explaination

Explanation:

#include <iostream>

#include <string.h>

using namespace st d;

class Package

{

protected:

//sender properities

char sname[10],saddress[50],scity[20],sstate[20];

long int szip;

//Receiver properities

char rname[10],raddress[50],rcity[20],rstate[20];

long int rzip;

//additonal datamembers

float weight,cost;

public:

Package() //Default constructor

{

strcpy(sname,"");strcpy(saddress,"");strcpy(scity,"");

strcpy(sstate,"");szip=0;

strcpy(rname,"");strcpy(raddress,"");strcpy(rcity,"");

strcpy(rstate,"");rzip=0;

weight=cost=0;

}

Package(char sn[10],char sa[50],char sc[20],char ss[20],long int sz,char rn[10],char ra[50],char rc[20],char rs[20],long int rz,float w,float c) //Constructor with parameter

{

strcpy(sname,sn);strcpy(saddress,sa);strcpy(scity,sc); //copying each parameter value to data member

strcpy(sstate,ss);szip=0;

strcpy(rname,rn);strcpy(raddress,ra);strcpy(rcity,rc);

strcpy(rstate,rs);rzip=0;

weight=w;cost=c;

}

float calculateCost() //calculating cost

{

return weight*cost;

}

};

class TwoDayPackage:public Package //Inheritance

{

float flatfee;

public:

TwoDayPackage(char sn[10],char sa[50],char sc[20],char ss[20],long int sz,char rn[10],char ra[50],char rc[20],char rs[20],long int rz,float w,float c,float ff) //Constructor with parameter

{

Package(sn,sa,sc,ss,sz,rn,ra,rc,rs,rz,w,c); //calling super class constructor

flatfee=ff; //copy last parameter

}

float calculateCost() //redefined calculateCost function

{

return (weight*cost)+flatfee; //return total cost

}

};

class OverNightPackage:public Package //Inheritance

{

float addfee;

public:

OverNightPackage(char sn[10],char sa[50],char sc[20],char ss[20],long int sz,char rn[10],char ra[50],char rc[20],char rs[20],long int rz,float w,float c,float a f) //constructor with parameter

{

Package(sn,sa,sc,ss,sz,rn,ra,rc,rs,rz,w,c); //calling super class constructor

addfee=a f; //copy last parameter

}

float calculateCost() //redefined calculateCost function

{

return (weight*cost)+addfee; //calculating total cost

}

};

int main()

{

Package package1("lou brown","1 main st","boston","ma",11111,"mary smith","7 elm st","new york","ny",22222,8.5,0.5); //creating objects

TwoDayPackage package2("lisa klein", "5 broadway", "somerville", "ma", 33333, "bob george", "21 pine rd", "cambridge", "ma", 44444, 10.5, .65, 2.0 );

OverNightPackage package3 ("ed lewis", "2 oak st", "boston", "ma", 55555, "don kelly", "9 main st", "denver", "co", 66666, 12.25, .7, .25 );

cout<<"\nPackage Cost : "<<package1.calculateCost(); //calling each cost

cout<<"\nTwoDay Package Cost : "<<package2.calculateCost();

cout<<"\nOvernight Package Cost : "<<package3.calculateCost();

return 0;

}

8 0
3 years ago
how to create use an array of Course objects instead of individual objects like course 1, course 2, etc
AURORKA [14]

Answer:

To save the course object instances in an array, use;

Course[] courses = new Course[7];

courses[0] = new Course("IT 145");

courses[1] = new Course("IT 200");

courses[2] = new Course("IT 201");

courses[3] = new Course("IT 270");

courses[4] = new Course("IT 315");

courses[5] = new Course("IT 328");

courses[6] = new Course("IT 330");

Explanation:

The java statement above assigns an array of size 7 with the course class constructor, then order courses are assigned to the respective indexes of the new array.

3 0
3 years ago
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