All categories

3 years ago

What is the order of the numbers form least to greatest?

Mathematics

2 answers:

Slav-nsk [51]3 years ago

7 0

Answer:

B < A < C < D

Step-by-step explanation:

We can easily order the numbers by using a shortcut. To do this, you just look at the exponents. The more negative the exponent, the lower the number is. The more positive the exponent is, the greater the number is.

WINSTONCH [101]3 years ago

7 0

Answer:

The answer is option 2.

Step-by-step explanation:

In a faster way to see this you can just look at the power :

A = -4

B = -6

C = 4

D = 5

B < A

A < C

C < D

So the order is B, A, C and D.

You might be interested in

Consider the surface z = x 2+4y 2+1. Suppose you are walking on this surface directly above a curve C in the xy-plane, where the

Bess [88]

With $x(t)=\cos t$ and $y(t)=\sin t$ , we have

$z(t)=x(t)^2+4y(t)^2+1$

$z(t)=\cos^2t+4\sin^2t+1$

$z(t)=3\sin^2t+2$

Then $z(t)$ has critical points where

$\dfrac{\mathrm dz}{\mathrm dt}=6\sin t\cos t=3\sin2t=0$

$\implies\sin2t=0\implies2t=n\pi\implies t=\dfrac{n\pi}2$

where $n$ is any integer.

$z(t)$ is increasing wherever $\sin2t>0$ , which happens for

$\dfrac{2n\pi}2$

$\boxed{n\pi$

5 0

3 years ago

Part 3. Identify the X intercepts for<br><br>y = (x+4)^2-9

RSB [31]

Answer:

x = -1 or x = -7

Step-by-step explanation:

y = (x + 4)^2 - 9

To find x-intercept, set y = 0

=> (x + 4)^2 - 9 = 0

=> ( x + 1)( x + 7) = 0

=> x = -1 or x = -7

7 0

3 years ago

Read 2 more answers

Find the perimeter of a rhombus the length of whose diagonals are 10 cm and 24 m.

Svet_ta [14]

check the picture below.

recall that in a rhombus, both diagonals bisect each other, namely cut each other in equal halves and at right-angles, so we end up with 4 right-triangles.

now, the sides in a rhombus are all equal, thus the perimeter is 13+13+13+13.

6 0

3 years ago

A pyramid is placed inside a prism as shown. The pyramid has the same base area, B, as the prism but half the height, h, of the

Alona [7]

The general formula of a pyramid with any base is 1/3 bh where b is the area of the base and h is the height. In this case, the height of the pyramid is said to be twice the height of the prism, h. Hence the area becomes 1/3 b*2h or equal to option A. 2/3 bh

4 0

3 years ago

Solve x2-14x+21=0 by completing the square

ankoles [38]

$x^2-14x+21=0\\\\x^2-2x\cdot7+7^2-7^2+21=0\\\\(x-7)^2-49+21=0\\\\(x-7)^2-28=0\\\\(x-7)^2=28\iff x-7=-\sqrt{28}\ \vee\ x-7=\sqrt{28}\\\\x=7-\sqrt{4\cdot7}\ \vee\ x=7+\sqrt{4\cdot7}\\\\x=7-2\sqrt7\ \vee\ x=7+2\sqrt7$

4 0

3 years ago