Answer: the probability of getting a number less than 3 and tails is P 1/6
Step-by-step explanation:
Assuming that the dice and the coin are normal ones, we can expect that the probability for each outcome is about the same.
For the coin we have 2 outcomes, heads and tails, then each outcome has a probability of 1/2
The dice has 6 outcomes, and each outcome has a probability of 1/6.
Then the probability of rolling a number less than 3 is equal to the probability of rolling a 1 plus the probability of rolling a 2.
P1 + P2 = 1/6 + 1/6 = 2/6 = 1/3.
The probability of getting tails with the coin is 1/2.
Now, the joint for both events is equal to the product of the probabilities of each event, this is:
P = (1/3)*(1/2) = 1/6
Full question:
Suppose SAT scores among students are normally distributed with a mean of 500 and a standard deviation of 100.
If a college says it admits only people with sat scores among the top 10%. how high a sat score does it take to be eligible?
Answer and explanation:
To find where SAT score of student falls in the test given mean and standard deviation of scores, we can calculate: x-500/100 where x is number of SAT score of students
A sat score in the top 10% region would have a score better than 90% of other SAT scores. Therefore 0.90 has a z score of 1.28
We use algebra to find the score to be eligible thus:
1.28=x-500/100
x-500=128
x=128+500
x=628
Therefore to be eligible, a student needs to score at least 628, and be in the top 10% of scores
12d-3d= 9d + 2 = 5
Subtract 2 from both sides you get
9d= 3
Divide by 9 by both sides
D= 0.33
In this equation, you are solving for y. Simply isolate the variable by adding 1/4 to each side. The -1/4 and 1/4 will cancel out on the right side of the equation, leaving only y:
5/4 = y - 1/4
5/4 + 1/4 = y - 1/4 + 1/4
6/4 = y
y = 6/4
Don't forget to simplify y:
y = 3/2
See picture below for the work shown
