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Ksivusya [100]
3 years ago
8

A chess club has 500 members but is losing 30 members each year. A computer club has 130 members and is gaining 20 members per y

ear. When will the two clubs have the same number of members? write thr equation you use, find the solution, and answer the question. equation: ____ solution:____ answer:_____

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
7 0
Equation:
500-30x=130+20x
Since you want to find when they are the same, you put an equal sign. Also, since one is gaining and the other is losing, you have an addition and subtraction sign.
Solution:
370= 50x
x=7.4
Answer:
After 7.4 years, the clubs will have the same members, which is 278 members.
Tell me if this helps!!

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Answer:

300K

Step-by-step explanation:

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2 years ago
Can someone please help me solve this?
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4 0
3 years ago
solve this system of linear equations. Separate the X- and Y- values with a comma. -9x+2y=-16 19x+3y=41​
Serjik [45]

Answer:

(2, 1)

Step-by-step explanation:

The best way to do this to avoid tedious fractions is to use the addition method (sometimes called the elimination method).  We will work to eliminate one of the variables.  Since the y values are smaller, let's work to get rid of those.  That means we have to have a positive and a negative of the same number so they cancel each other out.  We have a 2y and a 3y.  The LCM of those numbers is 6, so we will multiply the first equation by a 3 and the second one by a 2.  BUT they have to cancel out, so one of those multipliers will have to be negative.  I made the 2 negative.  Multiplying in the 3 and the -2:

3(-9x + 2y = -16)--> -27x + 6y = -48

-2(19x + 3y = 41)--> -38x - 6y = -82

Now you can see that the 6y and the -6y cancel each other out, leaving us to do the addition of what's left:

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x = 2

Now we will go back to either one of the original equations and sub in a 2 for x to solve for y:

19(2) + 3y = 41 so

38 + 3y = 41 and

3y = 3.  Therefore,

y = 1

The solution set then is (2, 1)

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