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2 years ago

What is the interquartile range (IQR) of the data set represented by this box

Mathematics

1 answer:

larisa [96]2 years ago

8 0

Answer:

36 :)

Step-by-step explanation:

First put the numbers in order from least to greatest.

0, 10, 20, 30, 32, 40, 42, 50, 56, 59, 60.

The median is 40 (middle)

Find the median of the two quartiles. 56 and 20.

Now subtract them. your answer is 36.

You might be interested in

The second on a watch is 14mm long. What area does it sweep through in 30 seconds

skad [1K]

Exact Area = 98pi

Approximate Area = 307.8760800518 (use calculator stored version of pi)

Approximate Area = 307.72 (using pi = 3.14)

Units are in square millimeters

======================================================

Explanation:

In 60 seconds, the hand sweeps out a full circle of radius 14. The area of this circle is

A = pi*r^2 = pi*14^2 = 196pi

Half of this is what the hand sweeps out in 30 seconds, so A/2 = (196pi)/2 = 98pi is the exact area it sweeps out. Your calculator would then show 98pi = 307.8760800518 approximately

If instead you use pi = 3.14, then the approximate area is 98*3.14 = 307.72

3 0

3 years ago

Expand and simplify ( √2 + 3)to the power of 2

11111nata11111 [884]

Answer:

Step-by-step explanation:

$(\sqrt{2}+3)^2=(\sqrt{2})^2 + 6\sqrt{2}+9 = 6\sqrt{2} +9+2=6\sqrt{2}+11$

hope this helps

5 0

3 years ago

All grizzly bear in the forest what type of sampling is this

zloy xaker [14]

Answer:

selective sample

Step-by-step explanation:

4 0

3 years ago

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar.

Anika [276]

Answer:

$\large\boxed{y=\dfrac{1}{2}x^2-2x+1}$

Step-by-step explanation:

The vertex form of an equation of a parabola:

$y=a(x-h)^2+k$

(h, k) - vertex

a - leading coefficient in equation y = ax² + bx + c

From the grap we can read coordinates of the vertex (2, -1) and y-intercept (0, 1).

Therefore h = 2, k = -1

Put the values of h, k and coordinates of the y-intercept to the equation of parabola:

$1=a(0-2)^2-1$ add 1 to both sides

$1+1=a(2)^2-1+1$

$2=4a$ divide both sides by 4

$\dfrac{2}{4}=\dfrac{4a}{4}\\\\\dfrac{1}{2}=a\to a=\dfrac{1}{2}$

Therefore we have the equation:

$y=\dfrac{1}{2}(x-2)^2-1$

Convert to the standard form:

$y=\dfrac{1}{2}(x-2)^2-1$ use (a - b)² = a² - 2ab + b²

$y=\dfrac{1}{2}(x^2-2(x)(2)+2^2)-1$

$y=\dfrac{1}{2}(x^2-4x+4)-1$ use the distributive property

$y=\dfrac{1}{2}x^2-\dfrac{1}{2}\cdot4x+\dfrac{1}{2}\cdot4-1$

$y=\dfrac{1}{2}x^2-2x+2-1$ combine like terms

$y=\dfrac{1}{2}x^2-2x+1$

5 0

3 years ago

What is an algebraic expression for each word phrase?

julia-pushkina [17]

Answer: a. n+16

b. n-22

c. 3xn

d. n/12

Step-by-step explanation:

5 0

3 years ago