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NISA [10]
3 years ago
15

In general, what would every child function have in common with the parent function f (x)= x?​

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
8 0

Step-by-step explanation:

If f(x) =x, is the father function, then all it's child function would be equally inclined to x and y-axis respectively.

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If x=5.25, what is the value of f(x)=10x+8
Nataly_w [17]

Answer:

f(x) = 10x + 8 \\ f(5.25) = 10(5.25) + 8 \\ f(5.25) = 52.5 + 8 \\ f(5.25) = 60.5

8 0
3 years ago
Combine like terms: 3t + 5 (3 + t) - 2t - 4
antoniya [11.8K]
3t + 15 + 5t - 2t - 4
6t + 15 - 4
6t + 11
3 0
3 years ago
Read 2 more answers
A club is choosing 2 members to serve on a committee. The club has nominated 2 women and 4 men. Based on chance alone, what is t
tekilochka [14]

Answer:

53.33% probability that one woman and one man will be chosen to be on the committee

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the members are chosen is not important, so we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

What is the probability that one woman and one man will be chosen to be on the committee?

Desired outcomes:

One woman, from a set of 2, and one man, from a set of 4. So

D = C_{2,1}*C_{4,1} = \frac{2!}{1!1!}*\frac{4!}{1!3!} = 8

Total outcomes:

Two members from a set of 2 + 4 = 6. So

T = C_{6,2} = \frac{6!}{2!4!} = 15

Probability:

p = \frac{D}{T} = \frac{8}{15} = 0.5333

53.33% probability that one woman and one man will be chosen to be on the committee

5 0
3 years ago
Please help with my last question.
Bas_tet [7]

Answer:

x = 8.3

y = 20.3

Step-by-step explanation:

21-\frac{2}{3} = 20\frac{1}{3} or 20.3

9-\frac{2}{3} = 8\frac{1}{3} or 8.3

6 0
2 years ago
Suppose you have a light bulb that emits 50 watts of visible light. (Note: This is not the case for a standard 50-watt light bul
natali 33 [55]

Answer:

0.049168726 light-years

Step-by-step explanation:

The apparent brightness of a star is

\bf B=\displaystyle\frac{L}{4\pi d^2}

where

<em>L = luminosity of the star (related to the Sun) </em>

<em>d = distance in ly (light-years) </em>

The luminosity of Alpha Centauri A is 1.519 and its distance is 4.37 ly.

Hence the apparent brightness of  Alpha Centauri A is

\bf B=\displaystyle\frac{1.519}{4\pi (4.37)^2}=0.006329728

According to the inverse square law for light intensity

\bf \displaystyle\frac{I_1}{I_2}=\displaystyle\frac{d_2^2}{d_1^2}

where

\bf I_1= light intensity at distance \bf d_1  

\bf I_2= light intensity at distance \bf d_2  

Let \bf d_2  be the distance we would have to place the 50-watt bulb, then replacing in the formula

\bf \displaystyle\frac{0.006329728}{50}=\displaystyle\frac{d_2^2}{(4.37)^2}\Rightarrow\\\\\Rightarrow d_2^2=\displaystyle\frac{0.006329728*(4.37)^2}{50}\Rightarrow d_2^2=0.002417564\Rightarrow\\\\\Rightarrow d_2=\sqrt{0.002417564}=\boxed{0.049168726\;ly}

Remark: It is worth noticing that Alpha Centauri A, though is the nearest star to the Sun, is not visible to the naked eye.

7 0
3 years ago
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