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harina [27]
3 years ago
13

The rules of a contest say there is 8% chance of winning a prize. Seven hundred people enter the contest. Predict how many peopl

e win a prize
Mathematics
1 answer:
vesna_86 [32]3 years ago
4 0

8%=0.08

0.08 times 700=56

56 people win a prize.

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Find the volume of a rectangular prism with the following dimension 2cm by 3cm by 4cm
Dafna11 [192]

Answer:

24 cm³

Step-by-step explanation:

V = LWH = 2 × 3 × 4 cm³ = 24 cm³

8 0
2 years ago
Read 2 more answers
Solve for the value of n <br> (9n) (8n+8)
Hatshy [7]

Answer:

undoable

Step-by-step explanation:

theres no =

3 0
2 years ago
What is the converse of the following statement? If a number is odd, it is not divisible by two.
tensa zangetsu [6.8K]

Converse in discrete mathematics is switching the hypothesis and conclusion of a conditional statement.

So the correct answer will be that If a number is not divisible by two, then it is an odd number. Which is option D.

The math converse of a statement switches the if and then, resulting in a statement that may or may not be true so we have no guarantee that the preposition is true or not.

8 0
3 years ago
Help! Pls answer correctly!​
defon

Answer:

<h3>numbers of Ostrich he keep = 725</h3>

<u>Step-by-step explanation:</u>

  • Area of field = 30 × 155 + 90 × 45
  • Area of field = 4650 + 4050
  • Area of field = 8700 m²

  • 1 ostrich need = 12 m²

numbers of Ostrich = 8700 ÷ 12

numbers of Ostrich = 725

8 0
2 years ago
A company has 200 machines. Each machine has 129 probability of not working. If you were to pick 40 machines randomly, the proba
alexgriva [62]

The probability that 5 would not be working is 0.18665, the probability that at least one machine would be working is 0.00602 and the probability that all would be working is 1.

Given a company has 200 machines. Each machine has a 12% probability of not working.

If we working pick 40 machines randomly then we have to find the probability that 5 would not be working, the probability that at least one machine would be working, and the probability that all would be working.

So

1) probability that 5 would not be working

C(40,5)·0.12⁵·0.88³⁵= 40!/(5!(40-5)!)·0.12⁵·0.88³⁵

                                ≈ 0.18665

2)  probability that at least one machine would be working

0.88⁴⁰ ≈ 0.00602

3) probability that all would be working

1 - 0.12⁴⁰ ≈ 1.0000

Learn more about probability here: brainly.com/question/24756209

#SPJ10

7 0
1 year ago
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