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4 years ago

PLEASE HELP

1 answer:

7 0

1. percent increase : (new number - original number) / (original number)...x 100

<span>(22 - 20) / 20 = 2/20 = 0.1.....0.1 x 100 = 10...so there is a 10% increase</span>

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You have four ice cubes in your cup of lemonade each ice cube has a length of 2 1/4 cm a width of 2 2/3 cm and a height of 2 cm

Margarita [4]

Answer: 6

Step-by-step explanation:

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3 years ago

Use the following graph of the function f(x) = −3x4 − x3 + 3x2 + x + 3 to answer this question: graph of negative 3 x to the fou

Serggg [28]

Answer:

The average rate of change from x=0 to x=1 for f(x) is 0.

Step-by-step explanation:

We are given the function $f(x)=-3x^{4}-x^{3}+3x^{2}+x+3$ .

Now, the rate average rate of change of a function from $y=x_{1}$ to $y=x_{2}$ is given by $\frac{f(x_{2})-f(x_{1})}{x_{2}-x_{1}}$ .

As, we need the rate of change from x = 0 to x = 1.

So, we will find the values of f(0) and f(1).

i.e. $f(0)=-3\times0^{4}-0^{3}+3\times0^{2}+0+3$ i.e. f(0) = 3

and $f(1)=-3\times1^{4}-1^{3}+3\times1^{2}+1+3$ i.e. $f(1)=-3-1+3+1+3$ i.e. f(1) = 3

Thus, the rate of change from x=0 to x=1 is $\frac{f(1)-f(0)}{1-0}$ i.e. $\frac{3-3}{1-0}$ i.e. 0

Hence, the average rate of change from x=0 to x=1 for f(x) is 0.

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4 years ago

Silicon wafers are scored and then broken into the many small microchips that will he mounted into circuits. Two breaking method

antoniya [11.8K]

Answer:

The estimate is $- 0.0265\le K \le 0.0465$

Method B this is because the faulty breaks are less

Step-by-step explanation:

The number of microchips broken in method A is $n_1 = 400$

The number of faulty breaks of method A is $X_1 = 32$

The number of microchips broken in method B is $n_2 = 400$

The number of faulty breaks of method A is $X_2 = 32$

The proportion of the faulty breaks to the total breaks in method A is

$p_1 = \frac{32}{400}$

$p_1 = 0.08$

The proportion of the faulty to the total breaks in method B is

$p_2 = \frac{28}{400}$

$p_2 = 0.07$

For this estimation the standard error is

$SE = \sqrt{ \frac{p_1 (1 - p_1)}{n_1} + \frac{p_2 (1- p_2 )}{n_2} } }$

substituting values

$SE = \sqrt{ \frac{0.08 (1 - 0.08)}{400} + \frac{0.07 (1- 0.07 )}{400} } }$

$SE = 0.0186$

The z-values of confidence coefficient of 0.95 from the z-table is

$z_{0.95} = 1.96$

The difference between proportions of improperly broken microchips for the two breaking methods is mathematically represented as

$K = [p_1 - p_2 ] \pm z_{0.95} * SE$

substituting values

$K = [0.08 - 0.07 ] \pm 1.96 *0.0186$

$K = - 0.0265 \ or \ K = 0.0465$

The interval of the difference between proportions of improperly broken microchips for the two breaking methods is

$- 0.0265\le K \le 0.0465$

3 0

3 years ago