Answer:
The solution in point form is (9,7) and the equation would be x+9, y=7
Step-by-step explanation:
By using moving the -4y to the right side and by flipping the signs you can turn the equation -x-4y=-37 into x=37-4y.
With this new equation you can use the substitution method and replace the x in -2x-5y=-53 with 37-4y, making it look like this: -2(37-4y)-5y=-53.
Then you solve for y getting y=7.
With the value of y, you can plug that into the equation x=37-4y so it will look like x=37-4(7)
Then you solve for x getting x=9
And with that you get the point (9,7)
Answer:
Length = 6
Width = 5.5
Step-by-step explanation:
Let's use the variable x to represent the width:
x = width
The question says that the length of the rectangle is "5 ft less than double the width". This length can be represented like this:
2x - 5 = length
To find the area of a rectangle, you multiply the width and length, so we are going to write an equation where we multiply the width and length and set it equal to 33 ft^2, which is the area:
(x)(2x - 5) = 33
Now use basic algebra to solve for x:
2x^2 - 5x = 33
2x^2 - 5x - 33 = 0
2x^2 + 6x - 11x - 33 = 0
(2x^2 + 6x) + (-11x - 33) = 0
2x(x + 3) - 11(x + 3) = 0
(2x - 11) (x + 3) = 0
x = 11/2, -3
x either equals 11/2 or -3. However, remember that x represents the width, and you can't have a negative number for a width, so x = 11/2 or 5.5.
Now plug in 5.5 to the length expression and simplify:
2(5.5) - 5
11 - 5 = 6
The length is 6 and the width is 5.5.
Hope this helps (●'◡'●)
To get the area, you need to multiply length and width together.
2052/54 = 38
38 is your width
38 (width) x 54 (length) = 2052 (area) True
hope this helps
