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3 years ago

A rectangular painting with a length of 54 centimeters has an area of 2,052 square centimeters.

1 answer:

6 0

To get the area, you need to multiply length and width together.

2052/54 = 38

38 is your width

38 (width) x 54 (length) = 2052 (area) True

hope this helps

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How to solve the system of equations algebraically for all values of x, y, and z

stich3 [128]

4x -3y + z = -10...............(1)
2x +y + 3z = 0...............(2)
-x +2y - 5z = 17...............(3)

First we multiply 3*(2) and add it to (1)
6x +3y +9z =0..................+(1)..................> 10x + 10z = -10......(4)

Then we multiply -2*(2) and add it to (3)
-4x -2y -6z =0 ...................+(3)................> -5x -11z = 17...........(5)

Multiply 2*(5) and add it to (4)
-10x -22z = 34...................+(4).................> -12 z = 24 ..............>>> z = -2

Substitute z in (4)............> 10x +10(-2) = -10.............................>>> x = 1

Substitute x and z in (2).....> 2(1) +y + 3(-2) = 0..................>>> y = 4

Solution (x,y,z) = (1,4,-2)

4 0

3 years ago

To find the height of a pole, a surveyor moves 160 feet away from the base of the pole and then, with a transit 6 feet tall, mea

Artyom0805 [142]

Answer:

306.8 feet

Step-by-step explanation:

Refer the attached figure .

A surveyor moves 160 feet away from the base of the pole i.e. ED = 160 m

Referring the image .

AC=ED=160 m

A transit i.e. AE is 6 feet tall.

AE = CD=6 feet

With a transmit the angle of elevation to the top of the pole to be 62° i.e. ∠BAC = 62°

To Find BC , use tigonometric ratio.

$Tan\theta = \frac{Perpendicular}{Base}$

$Tan 62^{\circ}=\frac{BC}{AC}$

$Tan 62^{\circ}=\frac{BC}{160}$

$1.88*160=BC$

$300.8=BC$

Now, the height of the pole = BC+CD =300.8+6=306.8 feet

Hence the height of the pole is 306.8 feet

7 0

3 years ago

Find the constant rate of change.

Aleonysh [2.5K]

Answer:

-1

Step-by-step explanation:

slope = y2-y1/x2-x1

(5,5) (7,3)

slope = 5-3/5-7 = 2/-2 = -1

3 0

3 years ago

183+6281+58+4561-44627-351+2427x56792x572952x527

Blizzard [7]

Answer:

The answer is 4.161844e+16

Step-by-step explanation:

8 0

3 years ago

A jet leaves Reno, Nevada and is headed toward Miami, Florida at a bearing of 100°. The distance between the two cities is appro

Likurg_2 [28]

So hmm, if you notice the picture below

"y" would be the opposite to the 10° angle, and "x" would its adjacent

Reno is "y" north and "x" west from Miami

$\bf sin(\theta)=\cfrac{opposite}{hypotenuse}\implies sin(10^o)=\cfrac{y}{2472}$ solve for "y", to see how much north

and $\bf cos(\theta)=\cfrac{adjacent}{hypotenuse}\implies cos(10^o)=\cfrac{x}{2472}$ solve for "x" to see how much west

make sure, that in both cases, your calculator is in Degree mode, since the angle is in degrees, as opposed to Radian mode

now... for the section B)

if notice the Reno-Miami line, and you were to draw a North line through it, anywhere in between, or at an endpoint like the in the picture at Reno, the "clockwise" angle, will always be the same, 100°

bear in mind ( no pun intended ), that Bearings use the North line, and the clockwise angle from it, as in the picture below

5 0

3 years ago