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sergij07 [2.7K]
3 years ago
6

is the diameter of a circle with center p. the coordinates of the endpoints of the diameter are (1, 3) and (6, 6). what are the

coordinates of point p?
Mathematics
1 answer:
Rashid [163]3 years ago
6 0
You need to find midpoint of the diameter. To find x coordinate you take (x1 + x2)/2 = (1+6)/2 = 7/2 And same thing for y. ( y1 + y2)/2 = (3+6)/2 = 9/2.
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Sundas made 2 out of her 5 shots she attempted. Find the percent of the shots she attempted.​
Rudik [331]

Answer:

<u>i think</u> it is 40%

Step-by-step explanation:

she made 2/5 shots so

2/5*2=4/10

i times it by 2 because its out of 100

4/10*10=40/100

then i times it by 10 to get to 100

(2/5 is not 2 divided by five it is 2 over 5 just incase u didnt know what i was talking about)

8 0
2 years ago
Lines a and b are parallel Line cis perpendicular to both line a and line b. Which
prohojiy [21]

Answer:

  see below

Step-by-step explanation:

The slopes of parallel lines are the same. The slopes of perpendicular lines are negative reciprocals of each other, hence their product is -1.

___

For the most part, the concept of adding slopes of lines does not relate to parallel or perpendicular lines in any way.

6 0
3 years ago
Read 2 more answers
A circular swimming pool has a radius of 28ft. There is a path all the way around the pool that's 4ft wide. A fence is going to
Natalka [10]

Answer:

Therefore 200.96 ft.of fencing are needed to go around the pool path.

Step-by-step explanation:

Given, a circular swimming pool has a radius of 28ft. There is a path all the way around the pool. The width of the path 4 ft.

The radius of the outside edge the pool path is

= Radius of the pool + The width of the path

= (28+4) ft

= 32 ft.

To find the length of fencing, we need to find the circumference of outside the pool path.

Here r= 32 ft

The circumference of outside edge of the pool path

=2\pi r

=(2\times 3.14 \times 32) ft

=200.96 ft.

Therefore 200.96 ft.of fencing are needed to go around the pool path.

3 0
3 years ago
How do I do this, I need to show work
kenny6666 [7]
Hello,

-2<1 ==> f(x)=3x²-1 =>f(-2)=3*(-2)²-1=3*4-1=12-1=11

3 0
3 years ago
En la división sintética sólo son tomados en cuenta los coeficientes del divisor?
Airida [17]

La división sintetica sirve para el cociente entre polinomios, la cual es particularmente util para cuando tenemos un numerador de grado alto y un denominador de grado 1.

Veremos que si, en la división sintética solo son tomados en cuenta los coeficientes del divisor.

Para explicarla, usaremos un ejemplo.

x^3 - 2x^2 + 5x + 3  será el <u>numerador</u>

x - 2 será el <u>denominador.</u>

Para poder aplicar la división sintetica, el maximo exponente en el <u>denominador </u>debe ser uno.

Así, nuestro cociente es:

\frac{x^3 - 2x^2 + 5x + 3}{x-2}

Procedemos a igualar el <u>denominador</u> a cero:

x - 2 = 0

x = 2

Ahora veremos los coeficientes del <u>numerador</u> (el <u>numerador </u>es el <u>divisor</u>).

Lo que debemos hacer es tomar cada coeficiente (comenzando por los que multiplican a los terminos con mayor exponente) y multiplicarlos por este número.

En este caso, el primer coeficiente es 1.

2*1 = 2

Ahora le sumamos esto al proximo coeficiente, que es -2:

-2 + 2 = 0

Multiplicamos esto por el valor de x, que es 2.

2*0 = 0

Ahora sumamos esto al proximo coeficiente, que es 5

5 + 0  = 5

Multiplicamos esto por el valor de x, que es 2:

5*2 = 10

Sumamos esto al ultimo coeficiente, que es 3.

10 + 3 = 13

Este ultimo valor es el residuo, y los primeros 3 números que obtuvimos son los coeficientes del cociente, entonces el cociente será:

1*x^2 + 0*x + 10 = x^2 + 10

Como vimos, solo usamos los coeficientes del numerador/divisor para realizar esta operación, por lo que si, solo los coeficientes del divisor son tomados en cuenta.

Si quieres aprender más, puedes leer:

brainly.com/question/10466403

3 0
2 years ago
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