20+2•(5+4^1) keep in mind of PEMDAS, so solve in the order P: Parentheses E: Exponents(in this case you would solve the exponent before the parentheses M: Multiplication D: Division A: Addition S: Subtraction
The answer is 10 Mark brainiest please
Answer:
<h2>9.2</h2>
Step-by-step explanation:
The distance formula is:
![d = \sqrt{(x2 - x1)^2 + (y2 - y1)^2](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%28x2%20-%20x1%29%5E2%20%2B%20%28y2%20-%20y1%29%5E2)
-4 - 2 = -6 squared = 36
4 - -3 = 7 squared = 49
36 + 49 = 85
about 9.2
I'm always happy to help :)
.04 hundredths. I cant believe i am still doing this in middle school.<span />
Answer:
<h2>
29</h2>
Step-by-step explanation:
![(20,21,x) \\Pythagoras -Theorem =\\a^2+b^2 = c^2\\\\20^2 + 21^2 = x^2\\400 + 441 = x^2\\841 = x^2\\Square -root-both-sides\\\sqrt{841} = \sqrt{x^2} \\29 = x\\\\x = 29](https://tex.z-dn.net/?f=%2820%2C21%2Cx%29%20%5C%5CPythagoras%20-Theorem%20%3D%5C%5Ca%5E2%2Bb%5E2%20%3D%20c%5E2%5C%5C%5C%5C20%5E2%20%2B%2021%5E2%20%3D%20x%5E2%5C%5C400%20%2B%20441%20%3D%20x%5E2%5C%5C841%20%3D%20x%5E2%5C%5CSquare%20-root-both-sides%5C%5C%5Csqrt%7B841%7D%20%3D%20%5Csqrt%7Bx%5E2%7D%20%5C%5C29%20%3D%20x%5C%5C%5C%5Cx%20%3D%2029)