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Diano4ka-milaya [45]
3 years ago
7

Please help a girl out

Mathematics
1 answer:
insens350 [35]3 years ago
4 0

Answer:

<em>Given-</em> y= -5x^2 +5

ATQ,

if it translated vertically downwards then the new function will be,

h = y - 5 = -5x^2

<u>PLEASE MARK AS BRAINLIEST AND FOLLOW IF IT HELPED YOU!</u>

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Molly bought a large basket of 6060 apples. When she got home, she found 44 rotten ones. If she goes back and buys 200200 more a
Flauer [41]

Answer: 13

Step-by-step explanation:

This is the correct question:

Molly bought a large basket of 60 apples. When she got home, she found 4 rotten ones. If she goes back and buys 200 more apples, how many rotten apples would she expect there to be?

From 60 apples, there are 4 rotten apples. This gives a fraction of:

= 4/60

= 0.06667

Therefore, when she buys 200 apples, tge number of rotten ones expected will be:

= 0.06667 × 200

= 13.334

= 13 approximately

4 0
3 years ago
Factor the expression completely -15t-6
Zielflug [23.3K]

Answer: -3(5t+2

Step-by-step explanation:

5 0
3 years ago
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What is the area of an equilateral triangle with apothem 3
Orlov [11]

Answer:

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6 0
4 years ago
How do you turn 2x+3y=20 into slope intercept form?
IRISSAK [1]

Answer:

The slope intercept form of the equation is:

y=-\frac{2}{3}x+\frac{20}{3}

Explanation:

Given the equation;

2x+3y=20

We want to re-write it in slope-intercept form;

\begin{gathered} y=mx+b \\ m=\text{slope} \\ b=\text{ y-intercept} \end{gathered}

To do that, let us make y the subject of formula in the given equation;

subtract 2x from both sides;

\begin{gathered} 2x-2x+3y=-2x+20 \\ 3y=-2x+20 \end{gathered}

then divide both sides by 3 ( the coefficient of y);

\begin{gathered} \frac{3y}{3}=\frac{-2x}{3}+\frac{20}{3} \\ y=-\frac{2}{3}x+\frac{20}{3} \end{gathered}

Therefore, the slope intercept form of the equation is;

y=-\frac{2}{3}x+\frac{20}{3}

6 0
1 year ago
Any one know this answer?
Andru [333]
B when the rocks and other minerals get composed into more little er components the form soil hope it helped
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