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Fynjy0 [20]
3 years ago
14

Hello ! Do you know the ways of arranging the letters in the word TOY?

Mathematics
1 answer:
Mamont248 [21]3 years ago
8 0

Answer:201525

Step-by-step explanation:

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Define a variable, write an equation and SOLVE the equation. Sandy had
notka56 [123]
The answer is 21 because 189 divided by 9 is 21
7 0
2 years ago
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Find the 4th term (x-y)^12
maria [59]

Answer:

The fourth term of the expansion is -220 * x^9 * y^3

Step-by-step explanation:

Question:

Find the fourth term in (x-y)^12

Solution:

Notation: "n choose k", or combination of k objects from n objects,

C(n,k) = n! / ( k! (n-k)! )

For example, C(12,4) = 12! / (4! 8!) = 495

Using the binomial expansion formula

(a+b)^n

= C(n,0)a^n + C(n,1)a^(n-1)b + C(n,2)a^(n-2)b^2 + C(n,3)a^(n-3)b^3 + C(n,4)a^(n-4)b^4 +....+C(n,n)b^n

For (x-y)^12, n=12, k=3, a=x, b=-y, and the fourth term is

C(n,3)a^(n-3)b^3

=C(12,3) * x^(12-3) * (-y)^(3)

= 220*x^9*(-y)^3

= -220 * x^9 * y^3

3 0
3 years ago
Evaluate each value expression for the given value of x : 22-x/5 , x=20<br><br> HURY!!!!!!!!!!!
ozzi
Answer= 18

22-20/5
22-4
=18
5 0
3 years ago
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(4) A spherical balloon is being inflated so that its diameter is increasing at a constant rate of 6 cm/min. How quickly is the
fredd [130]

In terms of its radius r, the volume of the balloon is

V(r)=\dfrac{4\pi}3r^3

The diameter d is twice the radius, so that in terms of its diameters, the balloon's volume is given by

V(d)=\dfrac{4\pi}3\left(\dfrac d2\right)^3=\dfrac\pi6d^3

Differentiate both sides with respect to time t:

\dfrac{\mathrm dV}{\mathrm dt}=\dfrac\pi2d^2\dfrac{\mathrm dd}{\mathrm dt}

The diameter increases at a rate of \frac{\mathrm dd}{\mathrm dt}=6\frac{\rm cm}{\rm min}. When the diameter is d=50\,\mathrm{cm}, we have

\dfrac{\mathrm dV}{\mathrm dt}=\dfrac\pi2(50\,\mathrm{cm})^2\left(6\frac{\rm cm}{\rm min}\right)=7500\pi\dfrac{\mathrm{cm}^3}{\rm min}

or about 23,562 cc/min (where cc = cubic centimeters)

5 0
3 years ago
Please help me with this math problem
elena55 [62]

When a tangent line (13.5 cm) and a secant (lines x + 8.45 cm) intersect then:


tangent line^2 = 8.45 * (8.45 + x)


13.5^2 = 71.4025 + 8.45 x


182.25 -71.4025 = 8.45x


8.45 x = 110.8475


x = 13.1180473373


x = 13.1 (rounded)


Source:

1728.com/circangl.htm




4 0
3 years ago
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