Question

Solve the system of equations​

Answer 1

Hey, there!!

Given that:

y = 3x.........(i)

$y = {x}^{2} + 3x - 16.......(ii)$

Putting the value of y in equation (ii)

${3x}^{} = {x}^{2} + 3x - 16$

${x }^{2} - 16$=0

$( {x)}^{2} - {4}^{2} = 0$

$(x + 4)(x - 4) = 0$

Therefore,

Either Or

(x+4)=0 (x-4)=0

x= -4 x= 4

so, x= (+ -)4

And if you wanna get value of y, just keep value of x in equation (i).

y= 3x

y= (3×4) or (3×-4)

y= 12 or -12

{As it is the quadratic equation it has two values. }

Hope it helps....