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Llana [10]
3 years ago
9

Thomas has a bag with 6 purple and 5 blue marbles. If his friend Nick pulls 2 marbles from the bag, what is the probability of h

im getting 2 purple marbles. 30/121 30/121 21/22 21/22 3/11 3/11 11/21
Mathematics
1 answer:
mars1129 [50]3 years ago
4 0

Answer: 3/11

Step-by-step explanation:

Number of purple marbles = 6

Number of blue marbles = 5

Total number of marbles = 6 + 5 = 11

The probability of picking the dust purple marble will be 6/11. After a purple marvel has been picked, there'll be 5 purple marbles left and the total number of marbles will be 10, therefore the probability of picking the second purple marble will be 5/10.

Therefore we then multiply the probability of picking the first purple marble by the probability of picking the second purple marble. This will be:

= 6/11 × 5/10

= 6/11 × 1/2

= 3/11

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Answer:

h is the function name; t is the input, or independent variable; and h(t) is the output, or dependent variable.

Step-by-step explanation:

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Jaime has 5 over 11 spaceof a project completed while Tim has finished 7 over 13 spaceof the same project.
faust18 [17]

Answer:

a. Tim has completed a greater amount of work.

b. Together they have completed \frac{142}{143} part of two projects.

Step-by-step explanation:

Let us assume that the project on which Jaime and Tim are working has x amount of space.

Now, given that Jaime has 5 over 11 space of a project completed while Tim has finished 7 over 13 space of the same project.

Therefore, Jaime has completed \frac{5x}{11} amount of space and Tim has finished \frac{7x}{13} amount of space.

a. Now, (7x) \times 11 > (5x) \times 13

⇒ \frac{7x}{13} > \frac{5x}{11}

Therefore, Tim has completed the greater amount of work. (Answer)

b. Together they have completed (\frac{7x}{13} + \frac{5x}{11}) = \frac{(7 \times 11 + 5 \times 13)}{13 \times 11} x = \frac{142}{143}x amount of space out of 2x amount of space. (Answer)

4 0
3 years ago
Will give brainliest to best answer.
Tomtit [17]
Problem One
Remark
If she doesn't mind having I kg left over, the minimum number would be 3 five kg boxes. If on the other hand, she must have exactly 14 kg then the minimum number is 6.

She needs 2 five kg boxes and 4 one kg boxes. <<<< Answer

Problem Two
There is a method of solving this that is called dimensional analysis. It is what should be used here. I'll do it at the end of the problem. In the meantime, you have to do it a slightly longer way.

1 portion = 100 grams.
x portions = 1kg which is 1000 grams.
x portions = 1000 grams.

Set up a proportion to find the number of servings in 1 kg
1 portion/x = 100 grams/1000 grams Cross multiply
1 * 1000 = 100 * x                                 Divide by 100
1000/100 = x
x = 10 servings in 1 kg.

So each kg produces 10 portions
1 kg / 10 portions = 20 kg / x portions Cross multiply
x * 1 = 10 * 20
x = 200 portions   <<<<< Answer

Dimensional Analysis
[1batch]*[1 portion/100g][1000g/kg][20kg/batch] the units cancel
1000 * 20 / 100 only the portions are left over.
200 portions is the answer.

Problem Three
1 kg = 1000 grams
x kg = 5000 grams  Cross multiply

1*5000 = 1000 x
x = 5 kg

1 parcel weighs 5 kg
x = 15 kg

15 kg = 5 x
x = 15/5
x = 3 

So he can carry 3 parcels per trip.

Since there are 5 such parcels, he will have to make 2 trips. The second one will not be a full load.
First Trip = 3 parcels
Second Trip = 2 parcels. <<<<Answer




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3 years ago
If the integers 23,-9,0-54,31 and 17 are arrange
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in ascending or descending order?

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