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Llana [10]
3 years ago
9

Thomas has a bag with 6 purple and 5 blue marbles. If his friend Nick pulls 2 marbles from the bag, what is the probability of h

im getting 2 purple marbles. 30/121 30/121 21/22 21/22 3/11 3/11 11/21
Mathematics
1 answer:
mars1129 [50]3 years ago
4 0

Answer: 3/11

Step-by-step explanation:

Number of purple marbles = 6

Number of blue marbles = 5

Total number of marbles = 6 + 5 = 11

The probability of picking the dust purple marble will be 6/11. After a purple marvel has been picked, there'll be 5 purple marbles left and the total number of marbles will be 10, therefore the probability of picking the second purple marble will be 5/10.

Therefore we then multiply the probability of picking the first purple marble by the probability of picking the second purple marble. This will be:

= 6/11 × 5/10

= 6/11 × 1/2

= 3/11

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A man finds that the angle of elevationof a building is 22º. After walking 20 m towards the building, he finds that the angle of
tensa zangetsu [6.8K]

Answer:

<em>The height of the building is 21.38 m</em>

Step-by-step explanation:

<u>Trigonometric Ratios</u>

The ratios of the sides of a right triangle are called trigonometric ratios.

The image attached shows the measures and angles provided in the problem. The first angle of elevation is y=22°, the man walks B=20 m and finds the new angle of elevation is x=33°.

It's required to find the height of the building H.

The tangent ratio relates the opposite side with the adjacent side of a given angle. Applying it to the larger triangle:

\displaystyle \tan y=\frac{\text{opposite leg}}{\text{adjacent leg}}

\displaystyle \tan 22^\circ=\frac{H}{D+B}

Multiplying by D+B:

\tan 22^\circ(D+B)=H

Dividing by tan 22°

\displaystyle D+B=\frac{H}{\tan 22^\circ}

Subtracting B:

\displaystyle D=\frac{H}{\tan 22^\circ}-B\qquad\qquad[1]

Applying to the smaller triangle:

\displaystyle \tan 33^\circ=\frac{H}{D}

Multiplying by D:

\tan 33^\circ D=H

Substituting from [1]:

\displaystyle \tan 33^\circ \left(\frac{H}{\tan 22^\circ}-B\right)=H

Substituting values:

\displaystyle 0.6494 \left(\frac{H}{0.4040}-20\right)=H

Operating:

1.6074H-12.988=H

1.6074H-H=12.988

0.6074H=12.988

H = 12.988/0.6074

H = 21.38 m

The height of the building is 21.38 m

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f(x) = 4x^2 - 16 + 3 combine light terms

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Hope I helped :)

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