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Marrrta [24]
2 years ago
11

16. A triangle has side lengths of 6, 8, and 10. Is it a right triangle? Explain.

Mathematics
1 answer:
inna [77]2 years ago
7 0

Answer:

yes it is bcz if you do 6^2+8^2 you get 10

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The point-slope form equation for this line is y₁ - 9 = 4 (x₁ - 1), or D.

Since these are all in point-slope form, all we need to do is find the slope and then input one value of (x, y) into the points. We start with the slope.

m = \frac{y₁ - y}{x₁ - x}

m = \frac{3 - 9}{-2 -1}

m = \frac{-6}{-3}

m = 2

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y₁ - 9 = 4 (x₁ - 1)

The equation that fits it is D., so that means that the only answer to this question is D.

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3 years ago
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alukav5142 [94]

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Step-by-step explanation:

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3 years ago
Complete the table below using the Midpoint and Distance Formulas.
Zielflug [23.3K]

Answer:

Coordinates of M = (2, -1)

Length of AB = 10 units

Step-by-step explanation:

Coordinates of the midpoint (M) of the distance between A(2, 4) and B(2, -6)

M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})

Let A(2, 4) = (x_1, y_1)

B(2, -6) = (x_2, y_2)

Thus:

M(\frac{2 + 2}{2}, \frac{4 +(-6)}{2})

M(\frac{4}{2}, \frac{-2}{2})

M(2, -1)

Length of AB:

Distance between A(2, 4) and B(2, -6):

AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

A(2, 4) = (x_1, y_1)

B(2, -6) = (x_2, y_2)

AB = \sqrt{(2 - 2)^2 + (-6 - 4)^2}

AB = \sqrt{(0)^2 + (-10)^2}

AB = \sqrt{0 + 100} = \sqrt{100}

AB = 10

5 0
3 years ago
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