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3 years ago

6

Please help solve! I tried but I’m messing this up, would really appreciate it!

1 answer:

STALIN [3.7K]3 years ago

7 0

Answer:

<em>K = </em> $\frac{4r}{n} -a$ <em> n </em> $\neq 0$ <em />

Step-by-step explanation:

We have our equation $r = \frac{n}{4} (a+K)$ and are looking for K

First we have to switch sides :

$\frac{n}{4} (a+K) = r$

Since we have a denominator of 4, we multiply both sides by 4 :

$n (a+K) = 4r$

We then divide both sides by n :

$a+K = \frac{4r}{n} ; n\neq 0$

Subtract a from both sides :

$K = \frac{4r}{n} -a; n\neq 0$

^^^

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