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Sever21 [200]
3 years ago
8

A baseball team has home games on Thursday and Saturday The two games together earn ​$4061.50 for the team. Thursday​'s game gen

erates ​$61.50 less than Saturday’s game. How much money was taken in at each​ game?
Mathematics
1 answer:
marta [7]3 years ago
7 0
The team made 2,061.50 at the first game and 2,000.00 at the second game. Because 2,000.00 would be 61.50 less than the amount made at the first game. You can check it by adding 2,061.50 + 2,000.00 which equals $4,061.50.
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A man goes into business for himself selling dog houses. The materials for the dog houses cost him $45 per house. He sells them
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Answer:

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Step-by-step explanation:

subtract 45 from 75, you get 30. multiply 30 by 20, and there is your answer.

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Write the following coordinates where they belong in the line segments below. Consider the graph below. Which of the following c
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Answer:

The option B (4 5/8,-2 3/4)  = (4.6 , -2.75) will be the coordinates belonging in the box.

Step-by-step explanation:

A.(4 3/4,-3 3/4) = (4.75,-3.75)

B.(4 5/8,-2 3/4)  = (4.6 , -2.75)

C.(4 1/4,-5 1/2)  = (4.25, -5.5)

D.(4 1/8,-2 3/5) = (4.125, -2.6)

The first point of line segment is: (5.5, -4.25)

second will be (4.75,-3.75)

third will be (4.6 , -2.75)

fourth will be (4.125, -2.6)

and fifth is  (3.75,-1.25)

The option C is not correct i.e not included in line segment.

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Which of the following shows that EFGH is a parallelogram for y=7 and z=9?
Anna35 [415]

Option B: m \angle F=m \angle G=120^{\circ} and m \angle E=60^{\circ}, so \angle E is supplementary to both \angle F and \angle G, so EFGH is a parallelogram.

Option C: m \angle F=m \angle G=120^{\circ} so EFGH is a parallelogram.

Option D: m \angle E+m \angle G=180^{\circ} so EFGH is a parallelogram.

Explanation:

Option A: m \angle E=m \angle F=60^{\circ} and m \angle G=120^{\circ} so \angle G is supplementary to both \angle E and \angle F, so EFGH is a parallelogram

Let us substitute y=7 and z=9 in m \angle E=(7y+11)^{\circ}, m \angle F=(17y+1)^{\circ} and m \angle G=(14z-6)^{\circ} to determine the exact measures the angles of the parallelogram.

Substituting, we get, m \angle E=60^{\circ}, m \angle F=m \angle G=120^{\circ}

Thus, m \angle E\neq m \angle F because the measures of these angles are not equal.

Hence, Option A is not the correct answer.

Option B:  m \angle F=m \angle G=120^{\circ} and m \angle E=60^{\circ}, so \angle E is supplementary to both \angle F and \angle G, so EFGH is a parallelogram.

Let us substitute y=7 and z=9 in m \angle E=(7y+11)^{\circ}, m \angle F=(17y+1)^{\circ} and m \angle G=(14z-6)^{\circ} to determine the exact measures the angles of the parallelogram.

Thus, substituting, we have, m \angle E=60^{\circ}, m \angle F=m \angle G=120^{\circ}

Hence, Option B is the correct answer.

Option C: m \angle F=m \angle G=120^{\circ} so EFGH is a parallelogram.

To determine the angles, let us substitute z=9 in  m \angle F=(17y+1)^{\circ} and m \angle G=(14z-6)^{\circ}

Thus, m \angle F=m \angle G=120^{\circ}

Since, the opposite angles of a parallelogram are equal, EFGH is a parallelogram.

Hence, Option C is the correct answer.

Option D: m \angle E+m \angle G=180^{\circ} so EFGH is a parallelogram.

Let us substitute y=7 and z=9 in m \angle E=(7y+11)^{\circ}, m \angle F=(17y+1)^{\circ} and m \angle G=(14z-6)^{\circ} to determine the exact measures the angles of the parallelogram.

Substituting, we have, m \angle E=60^{\circ}, m \angle F=m \angle G=120^{\circ}

Adding the angles E and G, we have,

m \angle E+m \angle G=60^{\circ}+120^{\circ}=180^{\circ}

By the property of parallelogram, any two adjacent angles add upto 180.

Thus, the adjacent angles E and G add upto 180.

Hence, Option D is the correct answer.

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