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Scilla [17]
3 years ago
13

What is the solution (ordered pair) for the graph ?

Mathematics
1 answer:
shtirl [24]3 years ago
3 0

Answer:

(2,0)

Step-by-step explanation:

Hi, I believe the answer is (2,0). The solution of the two equations are represented by their intersection. By finding that point, at when x is 2, and y 0, you can find the solution. Hope this helps!

You can also find the equations of the lines, then find the solution of them, but that's slower than the previous method.

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Anyone smart enough to do this ​
Nata [24]

Answer: B and F I believe

Step-by-step explanation:

7 0
3 years ago
-18=2+5x solve for x
Korvikt [17]

Answer:

x=-4

Step-by-step explanation:

-18=2+5x

Subtract 2 from both sides

-20=5x

-4=x

3 0
3 years ago
Read 2 more answers
You roll a 4-sided die repeatedly. On your odd-numbered rolls (1st,3rd,5th, etc.) you are victorious if you get a 4. On your eve
Sunny_sXe [5.5K]

Answer:

E (Y) = 3

Step-by-step explanation:

If a 4-sided die is being rolled repeatedly; and the odd-numbered rolls (1st 3rd,5th, etc.)

The probability of odd number roll will be, p(T) = \frac{1}{2}

However, on your even-numbered rolls, you are victorious if you get a 3 or 4. Also, the  probability of even number roll, p(U) = \frac{1}{2}

In order to  calculate: E (Y); We can say Y to be the number of times you roll.

We know that;

E (Y) = E ( Y|T ) p(T) + E ( Y|U ) p(U)

Let us calculate E ( Y|T ) and E ( Y|U )

Y|T ≅ geometric = \frac{1}{4}

Y|U ≅ geometric = \frac{1}{2}

also; x ≅ geometric (p)

∴ E (x) = \frac{1}{p}

⇒ \frac{Y}{T} = 4 ; also \frac{Y}{U} = 2

E (Y) = 4 × \frac{1}{2} + 2 ×

        = 2+1

E (Y) = 3

7 0
3 years ago
Which is the completely factored form of 12x^3-60x^2+4x-20​
Shkiper50 [21]

Answer:

(12x²+4)(x-5)

Step-by-step explanation:

To factor the expression factor by grouping.

(12x³ - 60x²) + (4x - 20)

12x²(x - 5) 4(x-5)

(12x²+4)(x-5)

6 0
3 years ago
Find the equation of the line with Slope = 6 and passing through (5,38). Write your equation in the form y =mx+b
laiz [17]

Hello.

We have:

  • A point that the line passes through
  • The slope of the line

Plug the values into the Point-Slope Formula:

\mathrm{y-y_1=m(x-x_1)}

\mathrm{y-38=6(x-5)}

\mathrm{y-38=6x-30}

\mathrm{y=6x-30+38}

\Large\boxed{\sf{ \ y=6x+8}}

I hope it helps.

Have a nice day.

\boxed{imperturbability}

5 0
2 years ago
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