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babymother [125]
4 years ago
15

Evaluate 2A - 3B for A = 6 and B = -3.

Mathematics
2 answers:
Rasek [7]4 years ago
6 0
2 (6) - 3 (-3)  , 12 - -9 , 12 + 9 , 21
Margaret [11]4 years ago
3 0
2A = 12 and 3B = -9
12 - (-9) = 21
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If 81 is added to a number the result is 39 less than three times the number
Deffense [45]

let x =the number

Step-by-step explanation:

81+x=3x-39

group like terms

81+39=3x-x

120=2x

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4 0
3 years ago
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A college conducts a common test for all the students. For the Mathematics portion of this test, the scores are normally distrib
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Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 502, \sigma = 115

The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:

X = 590:

Z = \frac{X - \mu}{\sigma}

Z = \frac{590 - 502}{115}

Z = 0.76

Z = 0.76 has a p-value of 0.7764.

X = 400:

Z = \frac{X - \mu}{\sigma}

Z = \frac{400 - 502}{115}

Z = -0.89

Z = -0.89 has a p-value of 0.1867.

0.7764 - 0.1867 = 0.5897 = 58.97%.

58.97% of students would be expected to score between 400 and 590.

More can be learned about the normal distribution at brainly.com/question/27643290

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6 0
2 years ago
A projectile is fired at such an angle that the vertical
svetoff [14.1K]

(a) The projectile remains in the air for 10 seconds

(b) It travels a horizontal distance of 600 meters

Step-by-step explanation:

A projectile is fired at such an angle that

1. The vertical  component of its velocity is 49 m/sec

2. The horizontal  component of its velocity is 60 m/sec

We need to find:

(a) How long the projectile remains in the air

(b) The horizontal distance it travels

∵ The vertical distance y = u_{y} t - \frac{1}{2} g t², where

u_{y} is the vertical  component of its velocity, g is the acceleration

of gravity and t is the time

∵ y = 0 ⇒ it return to the same initial height

∵ u_{y} = 49 m/s

∵ g = 9.8 m/s²

- Substitute these values in the rule above

∴ 0 = 49 t - \frac{1}{2} (9.8) t²

∴ 0 = 49 t - 4.9 t²

- Take t as a common factor

∴ 0 = t (49 - 4.9 t)

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∴ t = 0 ⇒ at initial position

∴ 49 - 4.9 t = 0

- Add 4.9 t to both side

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(a) The projectile remains in the air for 10 seconds

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∵ t = 10 seconds

∴ x = 60 × 10 = 600 meters

(b) It travels a horizontal distance of 600 meters

Learn more:

You can learn more about the component of velocity in brainly.com/question/4464845

#LearnwithBrainly

3 0
3 years ago
I need help on thiss
Lapatulllka [165]
1. = 5 animals

2. = 22 animals

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makvit [3.9K]

Answer:

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Step-by-step explanation:

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3 years ago
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