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3 years ago

6

What is the probability of taking 1 red stone out of a box containing 5 stones that are colored red, green, blue, yellow and bro

wn? 1/4 3/4 1/5 4/5

1 answer:

Luden [163]3 years ago

5 0

The probability of choosing the red stone is 1/5. Since there are five stones, and only one is red. Hope this helped. :D

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Discuss the differences between parametric and non-parametric tests?

lesya [120]

Nonparametric tests are also called distribution-free tests because they don't assume that your data follow a specific distribution. You may have heard that you should use nonparametric tests when your data don't meet the assumptions of the parametric test, especially the assumption about normally distributed data.

8 0

3 years ago

Janet bought a book for $19.95, and the tax was 6.25%. including tax how much did she pay round to nearest cent

drek231 [11]

Answer:$21.2

Step-by-step explanation:

multiply 19.25*6.25 then divide by 100 then add that answer onto 19.25 to then get an estimate of 21.2 dollars

3 0

3 years ago

Demarcus has to wrap a gift for his friend's birthday party. the gift is in a rectangular box with the dimensions shown below. h

Leya [2.2K]

The gift wrap needed by Damarcus = total surface area of a rectangular box = 1,048 in.².

<h3>What is the Total Surface Area of a Rectangular Box?</h3>

Total surface area (TSA) = 2(wl+hl+hw), where:

l = length
w = width
h = height of the box.

The amount of gift wrap needed to cover the whole box = total surface area of the rectangular box

l = 20 in.

w = 8 in.

h = 13 in.

Plug in the values into the formula for total surface area of a rectangular box:

TSA = 2(8×20 + 13×20 + 13×8)

TSA = 1,048 in.²

Therefore, the gift wrap needed by Damarcus = total surface area of a rectangular box = 1,048 in.².

Learn more about rectangular box on:

brainly.com/question/13103197

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1 year ago

If a sales person makes 6% commission, how much would they make from a $1,800 sale?

Liula [17]

108 bruh gimme my points

5 0

3 years ago

Read 2 more answers

Evaluate the sum of the following finite geometric series.

rjkz [21]

Answer:

$\large\boxed{\dfrac{156}{125}\approx1.2}$

Step-by-step explanation:

<h3>Method 1:</h3>

$\sum\limits_{n=1}^4\left(\dfrac{1}{5}\right)^{n-1}\\\\for\ n=1\\\\\left(\dfrac{1}{5}\right)^{1-1}=\left(\dfrac{1}{5}\right)^0=1\\\\for\ n=2\\\\\left(\dfrac{1}{5}\right)^{2-1}=\left(\dfrac{1}{5}\right)^1=\dfrac{1}{5}\\\\for\ n=3\\\\\left(\dfrac{1}{5}\right)^{3-1}=\left(\dfrac{1}{5}\right)^2=\dfrac{1}{25}\\\\for\ n=4\\\\\left(\dfrac{1}{5}\right)^{4-1}=\left(\dfrac{1}{5}\right)^3=\dfrac{1}{125}$

$\sum\limits_{n=1}^4\left(\dfrac{1}{5}\right)^{n-1}=1+\dfrac{1}{5}+\dfrac{1}{25}+\dfrac{1}{125}=\dfrac{125}{125}+\dfrac{25}{125}+\dfrac{5}{125}+\dfrac{1}{125}=\dfrac{156}{125}$

<h3>Method 2:</h3>

$\sum\limits_{n=1}^4\left(\dfrac{1}{5}\right)^{n-1}\to a_n=\left(\dfrac{1}{5}\right)^{n-1}\\\\\text{The formula of a sum of terms of a geometric series:}\\\\S_n=a_1\cdot\dfrac{1-r^n}{1-r}\\\\r-\text{common ratio}\to r=\dfrac{a_{n+1}}{a_n}\\\\a_{n+1}=\left(\dfrac{1}{5}\right)^{n+1-1}=\left(\dfrac{1}{5}\right)^n\\\\r=\dfrac{\left(\frac{1}{5}\right)^n}{\left(\frac{1}{5}\right)^{n-1}}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\r=\left(\dfrac{1}{5}\right)^{n-(n-1)}=\left(\dfrac{1}{5}\right)^{n-n+1}=\left(\dfrac{1}{5}\right)^1=\dfrac{1}{5}$

$a_1=\left(\dfrac{1}{5}\right)^{1-1}=\left(\dfrac{1}{5}\right)^0=1$

$\text{Substitute}\ a_1=1,\ n=4,\ r=\dfrac{1}{5}:\\\\S_4=1\cdot\dfrac{1-\left(\frac{1}{5}\right)^4}{1-\frac{1}{5}}=\dfrac{1-\frac{1}{625}}{\frac{4}{5}}=\dfrac{624}{625}\cdot\dfrac{5}{4}=\dfrac{156}{125}$

5 0

3 years ago