Ask question

Ask question

All categories

3 years ago

6

What is the probability of taking 1 red stone out of a box containing 5 stones that are colored red, green, blue, yellow and bro

wn? 1/4 3/4 1/5 4/5

1 answer:

Luden [163]3 years ago

5 0

The probability of choosing the red stone is 1/5. Since there are five stones, and only one is red. Hope this helped. :D

You might be interested in

Find the area of this rectangle.<br> 2<br> 13 cm<br> 口 Icm<br> 7 cm

Brums [2.3K]

Answer:

bro what

Step-by-step explanation:

5 0

3 years ago

(9x2 - 8x + 4) - (4x2 + 3x - 9) A. 13x2 - 11x + 5 B. 13x2 - 11x + 13 C. 5x2 - 5x + 13 D. 5x2 - 11x + 13

Troyanec [42]

The answer is d) 5x2-11x+13

4 0

3 years ago

Devon made a box with length x+1, width x+3, and height x-3. What is the volume of Devon's box as a function of x?

erica [24]

Answer:

(a)

$V=x^3+x^2-9x-9$

(b)

$x=10$

(c)

$x=\frac{7}{2}$

Step-by-step explanation:

we are given

length is x+1

$L=x+1$

width is x+3

$W=x+3$

height is x-3

$H=x-3$

(a)

we can use volume formula

$V=L\times W\times H$

now, we can plug it

$V=(x+1)\times (x+3)\times (x-3)$

now, we can simplify it

$V=x^3+x^2-9x-9$

(b)

we are given volume =1001

so, we can set V=1001

and then we can solve for x

$V=x^3+x^2-9x-9=1001$

now, we can factor it

$\left(x-10\right)\left(x^2+11x+101\right)=0$

$x-10=0$

$x=10$

(b)

we are given volume

so, we can set

$V=14\frac{5}{8}=\frac{14\times 8+5}{8}$

$V=\frac{117}{8}$

and then we can solve for x

$V=x^3+x^2-9x-9=\frac{117}{8}$

now, we can factor it

$8x^3+8x^2-72x-189=0$

$\left(2x-7\right)\left(4x^2+18x+27\right)=0$

$2x-7=0$

$x=\frac{7}{2}$

8 0

3 years ago

- Write a system of equations in which one equation could be multiplied by-2 and the

iris [78.8K]

2x+5y=9

3x+7y=13

6x+15y=27

-6x-14y=-26

y=1

x=2

6 0

2 years ago

Show that the equation 2x + 3 cos x + e ^ x = 0 has a root on the interval [- 1, 0]

ExtremeBDS [4]

If <em>x</em> = -1, you have

2(-1) + 3 cos(-1) + <em>e</em> ⁻¹ ≈ -0.0112136 < 0

and if <em>x</em> = 0, you have

2(0) + 3 cos(0) + <em>e</em> ⁰ = 4 > 0

The function <em>f(x)</em> = 2<em>x</em> + 3 cos(<em>x</em>) + <em>eˣ</em> is continuous over the real numbers, so the intermediate value theorem applies, and it says that there is some -1 < <em>c</em> < 0 such that <em>f(c)</em> = 0.

5 0

3 years ago