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aleksklad [387]
3 years ago
7

What is the equation of the line in slope-intercept form?

Mathematics
2 answers:
AnnyKZ [126]3 years ago
8 0
The correct answer is y = -2x + 16. In slope-intercept form, the formula is y = mx + b, where m is the slope and b is the y-intercept, or the place where the line crosses the y-axis. For this line, the y-intercept is positive 16, because the line crosses the y-axis at 16. Therefore, we know that the equation is y = mx + 16. Now, we just need to find the slope. By counting squares, we can see that the line goes down 4 and right 2. You can check this by taking two points on the line and subtracting them. For instance, the line goes from y 16 to y 12, which has a 4 unit difference. Therefore, the line goes down 4. It goes from x 0 to x 2, meaning that there is a difference of 2 between them, and, since the line is going right, the 2 is positive. Since slope = y/x, the slope is -4/2, or -2. Therefore, the slope is -2. 

Adding all this together, the slope in slope-intercept form is y = -2x + 16.

Hope this helps!
tia_tia [17]3 years ago
4 0
It's y=-2x + 16 because the graph starts at 16 and goes down 2 and over 2. The y-intecept is 16 and thats the only equation that has that as the y=intercept


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