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3 years ago

Find [g o f](x)=5x-5,g(x)=3x-2

Mathematics

1 answer:

wariber [46]3 years ago

7 0

Answer:

$→f(x) = 5x - 5 \\→g(x) = 3x - 2 \\ [gof](x) = g(f(x)) = 3(5x - 5) - 2 \\ [gof](x) = 15x - 15 - 2 = 15x - 17 \\ \boxed{[gof](x) = 15x - 17}✓$

[gof](x) = 15x - 17 is the right answer.

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How do you solve division easly

nlexa [21]

Answer:

division involves 5 steps:

D Divide

M Multiply

S Subtract

B Bring down

R Repeat or Remainder

Step-by-step explanation: i hope it helped

4 0

3 years ago

1.43 x 10*9 in standard form

QveST [7]

The exponent is 9, making it 10 to the power of 9. As the exponent is positive, the solution is a number greater than the origin or base number.

3 0

3 years ago

Read 2 more answers

If exactly 180 people sign up for a charter flight, Leisure World Travel Agency charges $298/person. However, if more than 180 p

lesantik [10]

Answer:

The max. revenue is $57,121.

This happens with 239 passengers.

The price of the ticket is $239 per person.

Step-by-step explanation:

Let the variable "P" denote the number of passengers.

If P=180, then the ticket cost is $298/person. Then the price is reduced by $1 for each additional person.

In general, if P=(180+x), then the ticket cost becomes (298-x) per person.

The revenue can be defined as the ticket cost multplied by the number of passengers:

$R=P*T=(180+x)(298-x)=53,640-180x+298x-x^2\\\\R(x)=-x^2+118x+53,640$

We can derive R and equal to zero to maximize the function.

$dR/dx=-2x+118=0\\\\x=118/2=59$

The amount of passengers is:

$P=180+x=180+59=239$

The price of the tickets is

$T=298-59=239$

The revenue is:

$R(59)=(180+59)(298-59)=239*239\\\\R(59)=57,121$

3 0

3 years ago

A problem contains the points (0,0),(1,-2) and (-1,-4). What is the equation of this parabola in standard form?

Bas_tet [7]

Answer:

The general equation of the parabola y = -3 x² + x

Step-by-step explanation:

Step(i):-

Given points are (0,0) , (1, -2) and ( -1 , -4 )

Given the standard parabola

y = ax²+ b x + c ...(i)

Passing through the point (0,0)

c = 0

Passing through the point (1,-2)

-2 = a(1) +b(1)

a + b = -2 ...(ii)

Passing through the point (-1, -4)

- 4 = a - b

a - b = -4 ...(iii)

Step(ii):-

Adding (ii) and (iii) equations , we get

2 a = -6

a = - 3

substitute a = - 3 in equation (ii)

-3 + b =-2

b = -2 + 3 = 1

Final answer:-

The general equation of the parabola

y = ax²+ b x + c

y = -3 x² + x + 0

y = -3 x² + x

4 0

3 years ago

Two components of a minicomputer have the following joint pdf for their useful lifetimes X and Y: f(x, y) = xe−x(1 + y) x ≥ 0 an

Yuri [45]

Answer:

For the given explanation we see that two life times are not independent

Step-by-step explanation:

probability for X (for x≥ 0)

$\int\limits^\infty_0 {xe^-^x^(^1^+^y^)} \, dy$

$-e^-^x\int\limits^\infty_0 {de^-^x^y} \,$

e⁻ˣ

Probability for X exceed 3

= $\int\limits^\infty_3 {f(x)dx$

= $\int\limits^\infty_3 {e^-^3 dx$

= $e^-^3$

probabilty for y≥ 0 is

$\int\limits^\infty_0 {xe^-^x^(^1^+^y^)} \, dx \\$

$\int\limits^\infty_0{-x/1+yd(e^-^x^(^1^+^y^))} \, =1/(1+y)² \\$

3 0

3 years ago