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3 years ago

Find [g o f](x)=5x-5,g(x)=3x-2

Mathematics

1 answer:

wariber [46]3 years ago

7 0

Answer:

$→f(x) = 5x - 5 \\→g(x) = 3x - 2 \\ [gof](x) = g(f(x)) = 3(5x - 5) - 2 \\ [gof](x) = 15x - 15 - 2 = 15x - 17 \\ \boxed{[gof](x) = 15x - 17}✓$

<u>[gof](x) = 15x - 17</u> is the right answer.

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zvonat [6]

The solutions are $x=15, x=-8$ and $x=9$

Explanation:

Part a: The equation is $\frac{1}{3} (5x-9)=2(\frac{1}{3} x+6)$

Let us find the value of x.

Multiply the terms within the bracket, we get,

$\frac{5}{3} x-3=\frac{2}{3} x+12$

Subtracting both sides by $\frac{2}{3} x$ , we have,

$\frac{3}{3} x-3=12$

Adding both sides by 3,

$x=15$

Thus, the solution of the equation $\frac{1}{3} (5x-9)=2(\frac{1}{3} x+6)$ is $x=15$

Part b: The equation is $4(3x+5)-3=9x-7$

Multiply the terms within the bracket, we get,

$12x+20-3=9x-7$

Subtracting both sides by 9x, we have,

$3x+17=-7$

Subtracting both sides by 17,

$3x=-24$

Dividing both sides by 3, we have,

$x=-8$

Thus, the solution of the equation $4(3x+5)-3=9x-7$ is $x=-8$

Part c: The equation is $5(x+7)-3(x-4)=7x+2$

Multiply the terms within the bracket, we get,

$5x+35-3x+12=7x+2$

Adding the like terms, we have,

$2x+47=7x+2$

Subtracting both sides by 2 and 2x, we get,

$45=5x$

Dividing both sides by 5, we have,

$x=9$

Thus, the solution of the equation $5(x+7)-3(x-4)=7x+2$ is $x=9$

8 0

4 years ago

Find the values of x and y.

True [87]

Its A
7x+7= 112

7x= 112-7
7x=105
x=105/7
x=15

To find y
180-112=68
68/4 =17
x= 15 y=17

6 0

4 years ago

Read 2 more answers

What is the radius of the circle x2+y2=12

valkas [14]

Answer:

Step-by-step explanation:

x²+y²=r²

r²=12

r=√12=2√3

7 0

4 years ago