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cestrela7 [59]
3 years ago
6

The center of a circle is at (−2, −7) and its radius is 6.

Mathematics
2 answers:
abruzzese [7]3 years ago
8 0
The correct option is C
prisoha [69]3 years ago
3 0
It is C. There are multiple ways you can arrive to this. 
You might remember the formula for the circrle: 
(x-a)^2+(y-b)^2=r^2
where (a,b) is the center of the circle and r is the radius. 
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I'm stuck on this please help!!
kvv77 [185]
The answer is D
\frac{12 {x}^{6}  {y}^{ - 4} {z}^{2}  }{3 {x}^{2}  {y}^{ - 6}  {z}^{3} } \\  =  \frac{4 {x}^{4}  {y}^{2} }{z}
5 0
4 years ago
3(2x + 7) - 2 (x + 5)
olga55 [171]

Answer:

Step-by-step explanation:

3(2x + 7) - 2 (x + 5)

need to distibute

5x+10-2x+3

combine like terms

3x+13

divide

x=4.3

5 0
3 years ago
Read 2 more answers
Why is the equation y-y1=m(x-x1) called the point-slope form?
MatroZZZ [7]

Answer:

The equation of the line with slope m = 2 and passing through the point (1, 1) will be:

y = 2x

Step-by-step explanation:

We know that the point-slope form of the line equation is

y-y_1=m\left(x-x_1\right)

where

  • m is the slope of the line
  • (x₁, y₁) is the point

The formula y-y_1=m\left(x-x_1\right) is termed as the point-slope form of the line equation because if we know one point on a certain line and the slope of that line, then we can easily get the line equation with this formula and, hence, determine all other points on the line.

For example, if we are given the point (1, 1) and slope m = 2

Then substituting the values m = 2 and the point (1, 2)

y-y_1=m\left(x-x_1\right)

y - 2 = 2(x-1)

y - 2 = 2x-2

y = 2x-2+2

y = 2x

Therefore, the equation of the line with slope m = 2 and passing through the point (1, 1) will be:

y = 2x

5 0
3 years ago
Would Y be the same as 146
Dima020 [189]

Answer:

Yes, y = 146

7 0
3 years ago
Read 2 more answers
What does 8-2(y+4)=1/2(8y-12) equal?
JulsSmile [24]

y = 1

8-2y - 8 = 4y - 6

-2y = 4y - 6

-6y = -6

y = 1

3 0
3 years ago
Read 2 more answers
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