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cestrela7 [59]
2 years ago
6

The center of a circle is at (−2, −7) and its radius is 6.

Mathematics
2 answers:
abruzzese [7]2 years ago
8 0
The correct option is C
prisoha [69]2 years ago
3 0
It is C. There are multiple ways you can arrive to this. 
You might remember the formula for the circrle: 
(x-a)^2+(y-b)^2=r^2
where (a,b) is the center of the circle and r is the radius. 
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Find the volume of this 1/4 cylinder after removing the inner part​
denpristay [2]

28-21=7

thickness = 2x7=14

volume =  \frac{1}{4} \pi \times h( {ro}^{2}  -  {ri}^{2} ) \\ =  \frac{1}{4}  \times 3.14 \times 14( {35}^{2}  -  {21}^{2} ) = 8620.276

3 0
2 years ago
TVs are measured by
kondor19780726 [428]

Answer:

Step-by-step explanation:

Diagonal is 60 inches, height is 24 inches so

60^2 = 24^2 + width^2

6.25 inches

4 0
2 years ago
If a polyhedron has 5 faces and 7 vertices, then it must have how many edges? Please show step-by-step work
Juli2301 [7.4K]

Answer:

10 edges

Step-by-step explanation:

we know that

The Euler's formula state that: In a polyhedron, the number of vertices, minus the number of edges, plus the number of faces, is equal to two

V - E + F = 2

in this problem  we have

V=7\\E=?\\F=5

substitute the given values

7 - E + 5 = 2

solve for E

Combine like terms in the left side

12 - E = 2

subtract 12 both sides

- E = -10

Multiply by -1 both sides

E =10

8 0
2 years ago
Passes through (3,-6) and (-1,2) slope intercept form?
IRISSAK [1]

Answer:

2/1

Step-by-step explanation:

8/4 which is also 2/1

7 0
2 years ago
Can I get some help please? <br><br><br> Thanks!
quester [9]
An ellipse (oval shape) is expressed by the following equation:

\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2}=1 where h is the x coordinate of the center and k is the y coordinate of the center. Furthermore, a is the horizontal distance from the center, and b is the vertical distance from the center. Lastly, c is the distance from the center to one of the foci (they are spaced apart equally).

We can find the foci by using a^2 - b^2 = c^2

36 - 11 = c^2

c =  \sqrt{25}  = 5

Since the k value in this case is 0, the y value of both foci are 0. Also, since h and k are both 0, we know the center of the ellipse is at the origin.

So the foci are (-5, 0) and (5, 0)

Hope this helps :)

3 0
3 years ago
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