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Usimov [2.4K]
4 years ago
5

John bikes 22 km per hour and starts at mile 10. Gwyn bikes 28 km per hour and starts at mile 0. Which system of linear equation

s represents this situation?
Example answer (not right)

A. John d=22t+
Gwym: d= 28t
History
2 answers:
storchak [24]4 years ago
7 0

If j is the distance in km John reaches after time t hours, and g is the same for Gwynn, the equations are

j=10+22t and g=28t.

If x is the distance at which they meet the equations form a system from which t, when they meet, can be calculated: 10+22t=28t, 6t=10, t=5/3=1 hour 40 minutes. And they meet at 28×5/3=10+22×5/3=46.67km.


stiks02 [169]4 years ago
7 0

answer is:

John: d=22t+10

Gwyn: d=28t

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