Answer:
Step-by-step explanation:
Given that at time t, the position of a body moving along the s-axis is sequalsnegative t cubed plus 15 t squared minus 72 t m
i.e.
Velocity is nothing but s'(t) = derivative of s
and acceleration is s"(t) = derivative of v(t)
a) v(t) =0 when t = 4 or 6
b)
a(t) =0 when t =5
c) Distance travelled by the body from 0 to 5 would be
i.e. 110 miles (distance cannot be negative)
The tension in the cable is given by the newton's first law will be 163.622 N.
<h3>What is newton's first law?</h3>The summation of the force is equal to zero.
The formula is given as
ΣF = 0
Where m is the mass of the body and a is the acceleration.
A 210-N mass is suspended from a horizontal beam by two cables that make angles of 29 degrees and 53 degrees with the beam.
Then the tension in the cable will be
Let T be the tension in the cable.
T sin 29° + T sin 53° – 210 = 0
On simplifying, we have
T (sin 29° + sin 53°) = 210
T = 163.622 N
More about the newton's first law link is given below.
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