<span>Answer:
I assume you're looking for a time-weighed average rather than just the [H(0) + H(60)]/2 average.
Havg = (1/60)â«[20+980e^(-0.1t)]dt (evaluated from 0 to 60)
Havg = (1/60)[20t - 98e^(-0.1t)] evaluated from 0 to 60
Havg = (1/60)[20(60) - 98e^(-6) - 20(0) + 98e^(0)] = 1297.76/60 = 21.629 Â°C</span>

8 0

2 years ago

okay this makes 0 sense... Show how you can solve the equation 3x=9 by multiplying each side by the reciprocal of 3... need to b

Allisa [31]

Answer:

x=3

Step-by-step explanation:

3x=9

Divide both sides by 3 and you get 1x=3 or basically x=3.

So the answer would be x=3.

7 0

2 years ago

Please need GEOMETRY help

natali 33 [55]

Multiply everything together in each question = and you’ll get your answer

Hope this helps!

6 0

3 years ago

The zeros of a parabola are –4 and 2, and (6, 10) is a point on the graph. Which equation can be solved to determine the value o

Fittoniya [83]

$\bf ~~~~~~\textit{parabola vertex form}
\\\\
\begin{array}{llll}
y=a(x- h)^2+ k\\\\
x=a(y- k)^2+ h
\end{array}
\qquad\qquad
vertex~~(\stackrel{}{ h},\stackrel{}{ k})\\\\
-------------------------------\\\\
\stackrel{\textit{zeros\qquad \qquad \qquad }}{
\begin{cases}
x=-4\implies &x+4=0\\
x=2\implies &x-2=0
\end{cases}}
\\\\\\
\stackrel{\textit{factored vertex form}}{y=a(x+4)(x-2)}\qquad (6,10)\textit{ we also know that }
\begin{cases}
x=6\\
y=10
\end{cases}
\\\\\\
10=a(6+4)(6-2)$

3 0

2 years ago

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