Answer:
4th option
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = 
x - 6 ← is in slope- intercept form
with slope m =
Given a line with slope m then the slope of a line perpendicular to it is
= - 
= - 
= - 
The equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b) a point on the line
Here m = - and (a, b ) = (- 2, 5 ) , then
y - 5 = - (x - (- 2) ) , that is
y - 5 = - (x + 2)
Answer:
The second one
Step-by-step explanation:
The answers for the exercise shown in the figure attached above, are shown
-The Compound inequality for the solution 1 is:
-2(x+1)≥-4 or 4x-7≥5
x≥1
x≥3
-The Compound inequality for the solution 2 is:
-6≤2x-8≤-2
1≤x≤3
-The Compound inequality for the solution 3 is:
3x-4≥5 or -5x+17≤12
x≥3
x<1
Answer:
I don't really know
Step-by-step explanation:
I don't really know but if you want to find out math questions try this website called wolfram alpha. It's great with those type of stuff.
1) A(-5,-3); B(-6,-1); C(-3,-1) ; D(-2,-3)
When a refection is done about x-axis, the values of the abscise x remain identical & the value of ordinate just change their signs:
A(-5,-3); A'(-5,+3)
B(-6,-1); B'(-6,+1)
C(-3,-1); C'(-3,+1)
D(-2,-3); D'(-2,+3)
2) A'B'C'D' is translated 3 UNITS RIGHT, that means the ordinated of A'B'C'D'
are the same but the abscises have been increased by 3 UNITS ;
A'(-5,+3) ==>A"(-2,3)
B'(-6,+1) ==>B"(-3,1)
C'(-3,+1) ==>C"(0,1)
D'(-2,+3) ==>D"(1,3)
