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Maurinko [17]
3 years ago
12

Mrs Jones uses 1/2 pint of milk on her cereal each morning.

Mathematics
2 answers:
EastWind [94]3 years ago
4 0
To do this, we need to divide 4/1 by 1/2. When dividing fractions we multiply the first fraction by the reciprocal of the second fraction. 

\frac{4}{1} (multiply) \frac{2}{1} = \frac{8}{1} (simplify) = 8

The answer is 8. 

Hope this helped! If you have anymore questions or don't understand, please comment or DM me. :)
stich3 [128]3 years ago
3 0
Mrs jones uses 1/4 of a pint of milk on her cereal each morning. 
<span>How many bowls of cereal will 4 pints of milk last ? </span>

<span>1/4x=4/1 </span>
<span>(4/1)/(1/4)=x </span>
<span>x=16, therefore 16 bowls 
hope this helps i just had a test with this question

</span>
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Answer:

  MK

Step-by-step explanation:

ML is the short side of right triangle MLK. MJ is the hypotenuse of right triangle MKJ. This gives you a clue that the ratios of interest are the short side to the hypotenuse. All these right triangles are similar, so ...

  ML/MK = MK/MJ . . . . . ratio of short side to hypotenuse is the same

  ML·MJ = MK² . . . . . . . cross multiply

  MK = √(ML·MJ) . . . . . the geometric mean of ML and MJ is MK

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3 years ago
Diego is solving the equation x^2-12x = 21
uysha [10]

Answer:

The solutions to the quadratic equations will be:

x=\sqrt{57}+6,\:x=-\sqrt{57}+6

Step-by-step explanation:

Given the expression

x^2-12x\:=\:21

Let us solve the equation by completing the square

x^2-12x\:=\:21

Add (-6)² to both sides

x^2-12x+\left(-6\right)^2=21+\left(-6\right)^2

simplify

x^2-12x+\left(-6\right)^2=57

Apply perfect square formula: (a-b)² = a²-2ab+b²

i.e.

x^2-12x+\left(-6\right)^2=\left(x-6\right)^2

so the expression becomes

\left(x-6\right)^2=57

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

solve

x-6=\sqrt{57}

add 6 to both sides

x-6+6=\sqrt{57}+6

Simplify

x=\sqrt{57}+6

also solving

x-6=-\sqrt{57}

add 6 to both sides

x-6+6=-\sqrt{57}+6

Simplify

x=-\sqrt{57}+6

Therefore, the solutions to the quadratic equation will be:

x=\sqrt{57}+6,\:x=-\sqrt{57}+6

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