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sveticcg [70]
3 years ago
6

Help me please thank you

Mathematics
2 answers:
alexandr402 [8]3 years ago
6 0
I think question 1 is -8
Ainat [17]3 years ago
5 0
First one is -8. 

Second one, I can't tell because I don't see it

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Anyone can help me with q6,7,8 Is supppse to be in sci but i press accidentally to math
lubasha [3.4K]
6) C
7) B
8) D

Hope this helped
5 0
3 years ago
Read 2 more answers
So i have to do this assignment and i have to divide 700 divided by 21 and i have to solve alot of steps its like long divison c
ValentinkaMS [17]
For long division, you would put 700 in the middle, since the fraction would be 700/21. Then you would figure out how many times 21 goes into 700. Then you would subtract 700 by the amount it would be before it went above 700 by multiplying it by 21. Then, if it is not able to go into 700 fully, you would put a decimal and bring a 0 down.
8 0
4 years ago
What is 9-(-5) please help me​
elena-14-01-66 [18.8K]

9-(-5)=

9 + 5 (because - - = +)

14

thus 9-(-5) = 14

4 0
4 years ago
What is the domain of the function of y=√x+8 -7
kirza4 [7]

Answer:

Step-by-step explanation:

Recall that the argument of the square root function y = √x must always be 0 or greater.

If you meant y=√x+8 -7, the domain is therefore [0, infinity).

But if you meant y=√(x+8) -7, the domain is [-8, infinity).

Those parentheses are important!

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%7B2%7D%5E%7Bm%7D%20%20%3D%20n%20" id="TexFormula1" title=" {2}^{m} = n " alt=" {2}^{m} =
sveta [45]

Answer:

\displaystyle n^3-\frac{1}{n^{2}}

Step-by-step explanation:

<u>Exponents Properties</u>

We need to recall the following properties of exponents:

(a^x)^y=(a^y)^x=a^{xy}

\displaystyle a^{-x}=\frac{1}{a^x}

We are given the expression:

2^m=n

We need to express the following expression in terms of n.

8^m-4^{-m}

It's necessary to modify the expression to use the given equivalence.

Recall 8=2^3 \text{ and }4 = 2^2. Thus:

(2^3)^m-(2^2)^{-m}

Applying the property:

(2^m)^3-(2^m)^{-2}

Substituting the given expression:

n^3-n^{-2}

Or, equivalently:

\mathbf{\displaystyle 8^m-4^{-m}= n^3-\frac{1}{n^{2}}}

5 0
3 years ago
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