This can be mathematically expressed to
250 + X = 1075
where X represents the parts you produce before the shift ends
Transpose 250 to the other side by subtracting each side by 250
Thus, it goes like this
X = 1075 - 250
X = 825
You produced 825 parts in the middle of the shift.
Answer:
Solve for a
a12−3(a−1)=11+a
Write the problem as a mathematical expression.
a12−3(a−1)=11+a
Simplify each term.
a12−3a+3=11+a
Graph each side of the equation. The solution is the x-value of the point of intersection.
a≈−1.1114621,1.23792371
Step-by-step explanation:
Answer: 1/6
Step-by-step explanation:
Because there's only one number that's greater than 5 on a numbered cube and that's '6'
I think it’s a im not that sure though
1. To solve this exercise, you must make a system of equations.
2. You have that f<span>our times a number minus twice another number is -8:
</span>
4x-2y=-8
3. And t<span>he sum of the two number is 19:
</span>
x+y=19
4. As you can see, you have two equations:
4x-2y=-8 (i)
x+y=19 (ii)
5. Let's clear the "x" from the equation (ii):
x=19-y
6. Now, you need to susbtitute x=19-y into the equation (i):
4x-2y=-8
4(19-y)-2y=-8
76-4y-2y=-8
76-6y=-8
-6y=-8-76
-6y=-84
y=-84/-6
y=14
7. You must susbstitute y=14 into the equation (ii) and clear "x":
x+y=19
x+14=19
x=19-14
x=5
The answer is: 5 and 14
