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DIA [1.3K]
1 year ago
14

A rectangle is 4xcm wide and 2cm long what do you notice

Mathematics
1 answer:
deff fn [24]1 year ago
4 0

The width of the rectangle is twice the length of the rectangle

<h3>How to compare the dimensions of the rectangle?</h3>

The given parameters are:

Width = 4 cm

Length = 2 cm

Express 4 cm as 2 * 2 cm

Width = 2 * 2 cm

Substitute Length = 2 cm in Width = 2 * 2 cm

Width = 2 * Length

This means that the width of the rectangle is twice the length of the rectangle

Hence, the true statement is that the width of the rectangle is twice the length of the rectangle

Read more about rectangles at:

brainly.com/question/25292087

#SPJ1

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Answer:

  • The center (2, 2.5), radius \sqrt{37} / 2

Step-by-step explanation:

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<u>Rewrite the given equation in the standard form:</u>

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Mr. Hodges wants to build a fence around his entire rectangular garden which has sides of 30 feet and 6 yards. How much fencing
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a father is now 38 years older than his son. Ten years ago he was twice as old as his son. let x represent the age of the son no
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The present age of father is 86 years old and present age of son is 48 years old

<em><u>Solution:</u></em>

Given that, a father is now 38 years older than his son

Ten years ago he was twice as old as his son

Let "x" be the age of son now

Therefore, from given,

Father age now = 38 + age of son now

Father age now = 38 + x

<em><u>Ten years ago he was twice as old as his son</u></em>

Age of son ten years ago = age of son now - 10

Age of son ten years ago = x - 10

Age of father ten years ago = 38 + x - 10

Then we get,

Age of father ten years ago = twice the age of son ten years ago

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Thus son age now is 48 years old

Father age now = x + 38 = 48 + 38 = 86

Thus present age of father is 86 years old and present age of son is 48 years old

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